%------------------------------------------------------------------------------ % File : Duper---1.0 % Problem : SYN052+1 : TPTP v9.2.0. Released v2.0.0. % Transfm : none % Format : tptp:raw % Command : duper %s % Computer : n010.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 300s % DateTime : Fri Oct 3 08:07:03 PM UTC 2025 % Result : Theorem 5.53s 5.70s % Output : Proof 5.53s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.03/0.11 % Problem : SYN052+1 : TPTP v9.2.0. Released v2.0.0. % 0.03/0.12 % Command : duper %s % 0.11/0.33 % Computer : n010.cluster.edu % 0.11/0.33 % Model : x86_64 x86_64 % 0.11/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.11/0.33 % Memory : 8042.1875MB % 0.11/0.33 % OS : Linux 3.10.0-693.el7.x86_64 % 0.11/0.33 % CPULimit : 300 % 0.11/0.33 % WCLimit : 300 % 0.11/0.33 % DateTime : Thu Oct 2 15:43:53 EDT 2025 % 0.11/0.33 % CPUTime : % 5.53/5.70 SZS status Theorem for theBenchmark.p % 5.53/5.70 SZS output start Proof for theBenchmark.p % 5.53/5.70 Clause #0 (by assumption #[]): Eq (Not ((∀ (X : Iota), Iff p (big_f X)) → Iff p (∀ (X1 : Iota), big_f X1))) True % 5.53/5.70 Clause #1 (by clausification #[0]): Eq ((∀ (X : Iota), Iff p (big_f X)) → Iff p (∀ (X1 : Iota), big_f X1)) False % 5.53/5.70 Clause #2 (by clausification #[1]): Eq (∀ (X : Iota), Iff p (big_f X)) True % 5.53/5.70 Clause #3 (by clausification #[1]): Eq (Iff p (∀ (X1 : Iota), big_f X1)) False % 5.53/5.70 Clause #4 (by clausification #[2]): ∀ (a : Iota), Eq (Iff p (big_f a)) True % 5.53/5.70 Clause #5 (by clausification #[4]): ∀ (a : Iota), Or (Eq p True) (Eq (big_f a) False) % 5.53/5.70 Clause #6 (by clausification #[4]): ∀ (a : Iota), Or (Eq p False) (Eq (big_f a) True) % 5.53/5.70 Clause #7 (by clausification #[3]): Or (Eq p False) (Eq (∀ (X1 : Iota), big_f X1) False) % 5.53/5.70 Clause #8 (by clausification #[3]): Or (Eq p True) (Eq (∀ (X1 : Iota), big_f X1) True) % 5.53/5.70 Clause #9 (by clausification #[7]): ∀ (a : Iota), Or (Eq p False) (Eq (Not (big_f (skS.0 0 a))) True) % 5.53/5.70 Clause #10 (by clausification #[9]): ∀ (a : Iota), Or (Eq p False) (Eq (big_f (skS.0 0 a)) False) % 5.53/5.70 Clause #11 (by clausification #[8]): ∀ (a : Iota), Or (Eq p True) (Eq (big_f a) True) % 5.53/5.70 Clause #12 (by superposition #[11, 5]): Or (Eq p True) (Or (Eq p True) (Eq True False)) % 5.53/5.70 Clause #13 (by clausification #[12]): Or (Eq p True) (Eq p True) % 5.53/5.70 Clause #14 (by eliminate duplicate literals #[13]): Eq p True % 5.53/5.70 Clause #16 (by backward demodulation #[14, 6]): ∀ (a : Iota), Or (Eq True False) (Eq (big_f a) True) % 5.53/5.70 Clause #17 (by backward demodulation #[14, 10]): ∀ (a : Iota), Or (Eq True False) (Eq (big_f (skS.0 0 a)) False) % 5.53/5.70 Clause #19 (by clausification #[16]): ∀ (a : Iota), Eq (big_f a) True % 5.53/5.70 Clause #20 (by clausification #[17]): ∀ (a : Iota), Eq (big_f (skS.0 0 a)) False % 5.53/5.70 Clause #21 (by superposition #[20, 19]): Eq False True % 5.53/5.70 Clause #22 (by clausification #[21]): False % 5.53/5.70 SZS output end Proof for theBenchmark.p %------------------------------------------------------------------------------