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SPASS---3.9.UNS-Ref.s

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%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : SYN057-1 : TPTP v8.1.0. Released v1.0.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n006.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Thu Jul 21 12:17:43 EDT 2022

% Result   : Unsatisfiable 0.19s 0.42s
% Output   : Refutation 0.19s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    5
%            Number of leaves      :    7
% Syntax   : Number of clauses     :   14 (   7 unt;   0 nHn;  14 RR)
%            Number of literals    :   26 (   0 equ;  14 neg)
%            Maximal clause size   :    4 (   1 avg)
%            Maximal term depth    :    1 (   1 avg)
%            Number of predicates  :    6 (   5 usr;   1 prp; 0-1 aty)
%            Number of functors    :    4 (   4 usr;   4 con; 0-0 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    big(a),
    file('SYN057-1.p',unknown),
    [] ).

cnf(2,axiom,
    ~ big_g(a),
    file('SYN057-1.p',unknown),
    [] ).

cnf(3,axiom,
    ( ~ big(u)
    | big_h(u) ),
    file('SYN057-1.p',unknown),
    [] ).

cnf(4,axiom,
    ( ~ big_i(u)
    | ~ big_j(u)
    | big(u) ),
    file('SYN057-1.p',unknown),
    [] ).

cnf(5,axiom,
    ( ~ big_h(u)
    | ~ big_i(u)
    | ~ big_h(v)
    | big_g(v) ),
    file('SYN057-1.p',unknown),
    [] ).

cnf(6,axiom,
    big_j(b),
    file('SYN057-1.p',unknown),
    [] ).

cnf(7,axiom,
    big_i(b),
    file('SYN057-1.p',unknown),
    [] ).

cnf(8,plain,
    ( ~ big_j(b)
    | big(b) ),
    inference(res,[status(thm),theory(equality)],[7,4]),
    [iquote('0:Res:7.0,4.1')] ).

cnf(9,plain,
    ( ~ big_h(u)
    | ~ big_h(b)
    | big_g(u) ),
    inference(res,[status(thm),theory(equality)],[7,5]),
    [iquote('0:Res:7.0,5.1')] ).

cnf(11,plain,
    big(b),
    inference(mrr,[status(thm)],[8,6]),
    [iquote('0:MRR:8.0,6.0')] ).

cnf(19,plain,
    ( ~ big_h(u)
    | ~ big(b)
    | big_g(u) ),
    inference(sor,[status(thm)],[9,3]),
    [iquote('0:SoR:9.1,3.1')] ).

cnf(20,plain,
    ( ~ big_h(u)
    | big_g(u) ),
    inference(ssi,[status(thm)],[19,6,7,11]),
    [iquote('0:SSi:19.1,6.0,7.0,11.0')] ).

cnf(21,plain,
    ~ big_h(a),
    inference(res,[status(thm),theory(equality)],[20,2]),
    [iquote('0:Res:20.1,2.0')] ).

cnf(22,plain,
    $false,
    inference(ssi,[status(thm)],[21,3,1]),
    [iquote('0:SSi:21.0,3.0,1.1')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12  % Problem  : SYN057-1 : TPTP v8.1.0. Released v1.0.0.
% 0.03/0.13  % Command  : run_spass %d %s
% 0.13/0.34  % Computer : n006.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit : 300
% 0.13/0.34  % WCLimit  : 600
% 0.13/0.34  % DateTime : Mon Jul 11 20:51:20 EDT 2022
% 0.13/0.34  % CPUTime  : 
% 0.19/0.42  
% 0.19/0.42  SPASS V 3.9 
% 0.19/0.42  SPASS beiseite: Proof found.
% 0.19/0.42  % SZS status Theorem
% 0.19/0.42  Problem: /export/starexec/sandbox2/benchmark/theBenchmark.p 
% 0.19/0.42  SPASS derived 5 clauses, backtracked 0 clauses, performed 0 splits and kept 11 clauses.
% 0.19/0.42  SPASS allocated 75596 KBytes.
% 0.19/0.42  SPASS spent	0:00:00.06 on the problem.
% 0.19/0.42  		0:00:00.04 for the input.
% 0.19/0.42  		0:00:00.00 for the FLOTTER CNF translation.
% 0.19/0.42  		0:00:00.00 for inferences.
% 0.19/0.42  		0:00:00.00 for the backtracking.
% 0.19/0.42  		0:00:00.00 for the reduction.
% 0.19/0.42  
% 0.19/0.42  
% 0.19/0.42  Here is a proof with depth 3, length 14 :
% 0.19/0.42  % SZS output start Refutation
% See solution above
% 0.19/0.42  Formulae used in the proof : clause_1 clause_2 clause_3 clause_4 clause_5 clause_6 clause_7
% 0.19/0.42  
%------------------------------------------------------------------------------