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Duper---1.0.THM-Prf.s

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%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : SYN079+1 : TPTP v9.2.0. Released v2.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n019.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Oct  3 08:07:08 PM UTC 2025

% Result   : Theorem 3.56s 3.77s
% Output   : Proof 3.56s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.12/0.12  % Problem    : SYN079+1 : TPTP v9.2.0. Released v2.0.0.
% 0.12/0.13  % Command    : duper %s
% 0.13/0.34  % Computer : n019.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit   : 300
% 0.13/0.34  % WCLimit    : 300
% 0.13/0.34  % DateTime   : Thu Oct  2 15:39:53 EDT 2025
% 0.13/0.34  % CPUTime    : 
% 3.56/3.77  SZS status Theorem for theBenchmark.p
% 3.56/3.77  SZS output start Proof for theBenchmark.p
% 3.56/3.77  Clause #0 (by assumption #[]): Eq (big_f (f a b) (f b c)) True
% 3.56/3.77  Clause #1 (by assumption #[]): Eq (big_f (f b c) (f a c)) True
% 3.56/3.77  Clause #2 (by assumption #[]): Eq (∀ (X Y Z : Iota), And (big_f X Y) (big_f Y Z) → big_f X Z) True
% 3.56/3.77  Clause #3 (by assumption #[]): Eq (Not (big_f (f a b) (f a c))) True
% 3.56/3.77  Clause #4 (by clausification #[2]): ∀ (a : Iota), Eq (∀ (Y Z : Iota), And (big_f a Y) (big_f Y Z) → big_f a Z) True
% 3.56/3.77  Clause #5 (by clausification #[4]): ∀ (a a_1 : Iota), Eq (∀ (Z : Iota), And (big_f a a_1) (big_f a_1 Z) → big_f a Z) True
% 3.56/3.77  Clause #6 (by clausification #[5]): ∀ (a a_1 a_2 : Iota), Eq (And (big_f a a_1) (big_f a_1 a_2) → big_f a a_2) True
% 3.56/3.77  Clause #7 (by clausification #[6]): ∀ (a a_1 a_2 : Iota), Or (Eq (And (big_f a a_1) (big_f a_1 a_2)) False) (Eq (big_f a a_2) True)
% 3.56/3.77  Clause #8 (by clausification #[7]): ∀ (a a_1 a_2 : Iota), Or (Eq (big_f a a_1) True) (Or (Eq (big_f a a_2) False) (Eq (big_f a_2 a_1) False))
% 3.56/3.77  Clause #10 (by superposition #[0, 8]): ∀ (a_1 : Iota), Or (Eq (big_f (f a b) a_1) True) (Or (Eq (big_f (f b c) a_1) False) (Eq False True))
% 3.56/3.77  Clause #11 (by clausification #[3]): Eq (big_f (f a b) (f a c)) False
% 3.56/3.77  Clause #13 (by clausification #[10]): ∀ (a_1 : Iota), Or (Eq (big_f (f a b) a_1) True) (Eq (big_f (f b c) a_1) False)
% 3.56/3.77  Clause #14 (by superposition #[13, 1]): Or (Eq (big_f (f a b) (f a c)) True) (Eq False True)
% 3.56/3.77  Clause #15 (by clausification #[14]): Eq (big_f (f a b) (f a c)) True
% 3.56/3.77  Clause #16 (by superposition #[15, 11]): Eq True False
% 3.56/3.77  Clause #18 (by clausification #[16]): False
% 3.56/3.77  SZS output end Proof for theBenchmark.p
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