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Twee---2.7.UNS-Prf.s

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%------------------------------------------------------------------------------
% File     : Twee---2.7
% Problem  : SYN117-1 : TPTP v9.3.1. Released v1.1.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : run_twee /export/starexec/sandbox2/benchmark/theBenchmark.p

% Computer : n006.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8046.5625MB
% OS       : Linux 6.8.0-71-generic
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Tue Sep 29 01:47:07 PM UTC 2026

% Result   : Unsatisfiable 5.95s 1.03s
% Output   : Proof 5.95s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.03  % Problem  : SYN117-1 : TPTP v9.3.1. Released v1.1.0.
% 0.00/0.04  % Command  : run_twee /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.06/0.18  % Computer : n006.cluster.edu
% 0.06/0.18  % Model    : x86_64 x86_64
% 0.06/0.18  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.06/0.18  % Memory   : 8046.5625MB
% 0.06/0.18  % OS       : Linux 6.8.0-71-generic
% 0.06/0.18  % CPULimit : 300
% 0.06/0.18  % WCLimit  : 300
% 0.06/0.18  % DateTime : Mon Sep 28 15:35:44 UTC 2026
% 0.06/0.19  % CPUTime  : 
% 0.06/0.19  Running run_twee /export/starexec/sandbox2/benchmark/theBenchmark.p
% 5.95/1.03  Command-line arguments: --no-flatten-goal
% 5.95/1.03  
% 5.95/1.03  % SZS status Unsatisfiable
% 5.95/1.03  
% 5.95/1.05  % SZS output start Proof
% 5.95/1.05  Axiom 1 (axiom_20): l0(a) = true.
% 5.95/1.05  Axiom 2 (axiom_37): n0(b, a) = true.
% 5.95/1.05  Axiom 3 (axiom_19): m0(X, d, Y) = true.
% 5.95/1.05  Axiom 4 (ifeq_axiom): ifeq(X, X, Y, Z) = Y.
% 5.95/1.05  Axiom 5 (rule_244): ifeq(n2(X), true, p3(X, X, X), true) = true.
% 5.95/1.05  Axiom 6 (rule_088): ifeq(l0(a), true, p1(a, a, a), true) = true.
% 5.95/1.05  Axiom 7 (rule_002): ifeq(n0(X, Y), true, l1(Y, Y), true) = true.
% 5.95/1.05  Axiom 8 (rule_137): ifeq(p1(X, Y, Z), true, n2(Z), true) = true.
% 5.95/1.05  Axiom 9 (rule_006): ifeq(m0(X, X, Y), true, m1(Y, Y, Y), true) = true.
% 5.95/1.05  Axiom 10 (rule_150): ifeq(m1(X, X, Y), true, p2(Y, Y, Y), true) = true.
% 5.95/1.05  Axiom 11 (rule_267): ifeq(p2(X, Y, Z), true, r3(X, Z, X), true) = true.
% 5.95/1.05  Axiom 12 (rule_300): ifeq(s4(X), true, ifeq(r3(Y, Z, Z), true, k5(Z), true), true) = true.
% 5.95/1.05  Axiom 13 (rule_299): ifeq(p3(X, Y, Z), true, ifeq(l1(W, Y), true, s4(W), true), true) = true.
% 5.95/1.05  
% 5.95/1.05  Goal 1 (prove_this): k5(e) = true.
% 5.95/1.05  Proof:
% 5.95/1.05    k5(e)
% 5.95/1.05  = { by axiom 4 (ifeq_axiom) R->L }
% 5.95/1.05    ifeq(true, true, k5(e), true)
% 5.95/1.05  = { by axiom 13 (rule_299) R->L }
% 5.95/1.05    ifeq(ifeq(p3(a, a, a), true, ifeq(l1(a, a), true, s4(a), true), true), true, k5(e), true)
% 5.95/1.05  = { by axiom 4 (ifeq_axiom) R->L }
% 5.95/1.05    ifeq(ifeq(ifeq(true, true, p3(a, a, a), true), true, ifeq(l1(a, a), true, s4(a), true), true), true, k5(e), true)
% 5.95/1.05  = { by axiom 8 (rule_137) R->L }
% 5.95/1.05    ifeq(ifeq(ifeq(ifeq(p1(a, a, a), true, n2(a), true), true, p3(a, a, a), true), true, ifeq(l1(a, a), true, s4(a), true), true), true, k5(e), true)
% 5.95/1.05  = { by axiom 4 (ifeq_axiom) R->L }
% 5.95/1.05    ifeq(ifeq(ifeq(ifeq(ifeq(true, true, p1(a, a, a), true), true, n2(a), true), true, p3(a, a, a), true), true, ifeq(l1(a, a), true, s4(a), true), true), true, k5(e), true)
% 5.95/1.05  = { by axiom 1 (axiom_20) R->L }
% 5.95/1.05    ifeq(ifeq(ifeq(ifeq(ifeq(l0(a), true, p1(a, a, a), true), true, n2(a), true), true, p3(a, a, a), true), true, ifeq(l1(a, a), true, s4(a), true), true), true, k5(e), true)
% 5.95/1.05  = { by axiom 6 (rule_088) }
% 5.95/1.05    ifeq(ifeq(ifeq(ifeq(true, true, n2(a), true), true, p3(a, a, a), true), true, ifeq(l1(a, a), true, s4(a), true), true), true, k5(e), true)
% 5.95/1.05  = { by axiom 4 (ifeq_axiom) }
% 5.95/1.05    ifeq(ifeq(ifeq(n2(a), true, p3(a, a, a), true), true, ifeq(l1(a, a), true, s4(a), true), true), true, k5(e), true)
% 5.95/1.05  = { by axiom 5 (rule_244) }
% 5.95/1.05    ifeq(ifeq(true, true, ifeq(l1(a, a), true, s4(a), true), true), true, k5(e), true)
% 5.95/1.05  = { by axiom 4 (ifeq_axiom) }
% 5.95/1.05    ifeq(ifeq(l1(a, a), true, s4(a), true), true, k5(e), true)
% 5.95/1.05  = { by axiom 4 (ifeq_axiom) R->L }
% 5.95/1.05    ifeq(ifeq(ifeq(true, true, l1(a, a), true), true, s4(a), true), true, k5(e), true)
% 5.95/1.05  = { by axiom 2 (axiom_37) R->L }
% 5.95/1.05    ifeq(ifeq(ifeq(n0(b, a), true, l1(a, a), true), true, s4(a), true), true, k5(e), true)
% 5.95/1.05  = { by axiom 7 (rule_002) }
% 5.95/1.05    ifeq(ifeq(true, true, s4(a), true), true, k5(e), true)
% 5.95/1.05  = { by axiom 4 (ifeq_axiom) }
% 5.95/1.05    ifeq(s4(a), true, k5(e), true)
% 5.95/1.05  = { by axiom 4 (ifeq_axiom) R->L }
% 5.95/1.05    ifeq(s4(a), true, ifeq(true, true, k5(e), true), true)
% 5.95/1.05  = { by axiom 11 (rule_267) R->L }
% 5.95/1.05    ifeq(s4(a), true, ifeq(ifeq(p2(e, e, e), true, r3(e, e, e), true), true, k5(e), true), true)
% 5.95/1.05  = { by axiom 4 (ifeq_axiom) R->L }
% 5.95/1.05    ifeq(s4(a), true, ifeq(ifeq(ifeq(true, true, p2(e, e, e), true), true, r3(e, e, e), true), true, k5(e), true), true)
% 5.95/1.05  = { by axiom 9 (rule_006) R->L }
% 5.95/1.05    ifeq(s4(a), true, ifeq(ifeq(ifeq(ifeq(m0(d, d, e), true, m1(e, e, e), true), true, p2(e, e, e), true), true, r3(e, e, e), true), true, k5(e), true), true)
% 5.95/1.05  = { by axiom 3 (axiom_19) }
% 5.95/1.05    ifeq(s4(a), true, ifeq(ifeq(ifeq(ifeq(true, true, m1(e, e, e), true), true, p2(e, e, e), true), true, r3(e, e, e), true), true, k5(e), true), true)
% 5.95/1.05  = { by axiom 4 (ifeq_axiom) }
% 5.95/1.05    ifeq(s4(a), true, ifeq(ifeq(ifeq(m1(e, e, e), true, p2(e, e, e), true), true, r3(e, e, e), true), true, k5(e), true), true)
% 5.95/1.05  = { by axiom 10 (rule_150) }
% 5.95/1.05    ifeq(s4(a), true, ifeq(ifeq(true, true, r3(e, e, e), true), true, k5(e), true), true)
% 5.95/1.05  = { by axiom 4 (ifeq_axiom) }
% 5.95/1.05    ifeq(s4(a), true, ifeq(r3(e, e, e), true, k5(e), true), true)
% 5.95/1.05  = { by axiom 12 (rule_300) }
% 5.95/1.05    true
% 5.95/1.05  % SZS output end Proof
% 5.95/1.05  
% 5.95/1.05  RESULT: Unsatisfiable (the axioms are contradictory).
%------------------------------------------------------------------------------