%------------------------------------------------------------------------------
% File : Twee---2.7
% Problem : SYN146-1 : TPTP v9.3.1. Released v1.1.0.
% Transfm : none
% Format : tptp:raw
% Command : run_twee /export/starexec/sandbox2/benchmark/theBenchmark.p
% Computer : n013.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8046.5625MB
% OS : Linux 6.8.0-71-generic
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Tue Sep 29 01:47:11 PM UTC 2026
% Result : Unsatisfiable 2.51s 0.63s
% Output : Proof 2.51s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.03 % Problem : SYN146-1 : TPTP v9.3.1. Released v1.1.0.
% 0.00/0.04 % Command : run_twee /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.08/0.17 % Computer : n013.cluster.edu
% 0.08/0.17 % Model : x86_64 x86_64
% 0.08/0.17 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.08/0.17 % Memory : 8046.5625MB
% 0.08/0.17 % OS : Linux 6.8.0-71-generic
% 0.08/0.17 % CPULimit : 300
% 0.08/0.17 % WCLimit : 300
% 0.08/0.17 % DateTime : Mon Sep 28 15:36:21 UTC 2026
% 0.08/0.17 % CPUTime :
% 0.08/0.17 Running run_twee /export/starexec/sandbox2/benchmark/theBenchmark.p
% 2.51/0.63 Command-line arguments: --no-flatten-goal
% 2.51/0.63
% 2.51/0.63 % SZS status Unsatisfiable
% 2.51/0.63
% 2.51/0.63 % SZS output start Proof
% 2.51/0.63 Axiom 1 (axiom_24): l0(c) = true.
% 2.51/0.63 Axiom 2 (ifeq_axiom): ifeq(X, X, Y, Z) = Y.
% 2.51/0.63 Axiom 3 (rule_049): ifeq(l0(c), true, n1(c, c, c), true) = true.
% 2.51/0.63
% 2.51/0.63 Goal 1 (prove_this): n1(X, c, Y) = true.
% 2.51/0.63 The goal is true when:
% 2.51/0.63 X = c
% 2.51/0.63 Y = c
% 2.51/0.63
% 2.51/0.63 Proof:
% 2.51/0.63 n1(c, c, c)
% 2.51/0.63 = { by axiom 2 (ifeq_axiom) R->L }
% 2.51/0.63 ifeq(true, true, n1(c, c, c), true)
% 2.51/0.63 = { by axiom 1 (axiom_24) R->L }
% 2.51/0.63 ifeq(l0(c), true, n1(c, c, c), true)
% 2.51/0.63 = { by axiom 3 (rule_049) }
% 2.51/0.63 true
% 2.51/0.63 % SZS output end Proof
% 2.51/0.63
% 2.51/0.63 RESULT: Unsatisfiable (the axioms are contradictory).
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