%------------------------------------------------------------------------------
% File : Twee---2.7
% Problem : SYN165-1 : TPTP v9.3.1. Released v1.1.0.
% Transfm : none
% Format : tptp:raw
% Command : run_twee /export/starexec/sandbox/benchmark/theBenchmark.p
% Computer : n001.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8046.5625MB
% OS : Linux 6.8.0-71-generic
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Tue Sep 29 01:47:13 PM UTC 2026
% Result : Unsatisfiable 2.62s 0.60s
% Output : Proof 2.62s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.02 % Problem : SYN165-1 : TPTP v9.3.1. Released v1.1.0.
% 0.00/0.04 % Command : run_twee /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.11/0.15 % Computer : n001.cluster.edu
% 0.11/0.15 % Model : x86_64 x86_64
% 0.11/0.15 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.11/0.15 % Memory : 8046.5625MB
% 0.11/0.15 % OS : Linux 6.8.0-71-generic
% 0.11/0.15 % CPULimit : 300
% 0.11/0.15 % WCLimit : 300
% 0.11/0.15 % DateTime : Mon Sep 28 15:43:18 UTC 2026
% 0.11/0.15 % CPUTime :
% 0.11/0.15 Running run_twee /export/starexec/sandbox/benchmark/theBenchmark.p
% 2.62/0.60 Command-line arguments: --flatten-regeneralise
% 2.62/0.60
% 2.62/0.60 % SZS status Unsatisfiable
% 2.62/0.60
% 2.62/0.60 % SZS output start Proof
% 2.62/0.60 Axiom 1 (axiom_20): l0(a) = true.
% 2.62/0.60 Axiom 2 (ifeq_axiom): ifeq(X, X, Y, Z) = Y.
% 2.62/0.60 Axiom 3 (rule_088): ifeq(l0(a), true, p1(a, a, a), true) = true.
% 2.62/0.60
% 2.62/0.60 Goal 1 (prove_this): p1(X, a, X) = true.
% 2.62/0.60 The goal is true when:
% 2.62/0.60 X = a
% 2.62/0.60
% 2.62/0.60 Proof:
% 2.62/0.60 p1(a, a, a)
% 2.62/0.60 = { by axiom 2 (ifeq_axiom) R->L }
% 2.62/0.60 ifeq(true, true, p1(a, a, a), true)
% 2.62/0.60 = { by axiom 1 (axiom_20) R->L }
% 2.62/0.60 ifeq(l0(a), true, p1(a, a, a), true)
% 2.62/0.60 = { by axiom 3 (rule_088) }
% 2.62/0.60 true
% 2.62/0.60 % SZS output end Proof
% 2.62/0.60
% 2.62/0.60 RESULT: Unsatisfiable (the axioms are contradictory).
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