%------------------------------------------------------------------------------
% File : Twee---2.7
% Problem : SYN183-1 : TPTP v9.3.1. Released v1.1.0.
% Transfm : none
% Format : tptp:raw
% Command : run_twee /export/starexec/sandbox/benchmark/theBenchmark.p
% Computer : n003.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8046.5625MB
% OS : Linux 6.8.0-71-generic
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Tue Sep 29 01:47:15 PM UTC 2026
% Result : Unsatisfiable 0.15s 0.90s
% Output : Proof 0.15s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.02 % Problem : SYN183-1 : TPTP v9.3.1. Released v1.1.0.
% 0.00/0.03 % Command : run_twee /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.09/0.16 % Computer : n003.cluster.edu
% 0.09/0.16 % Model : x86_64 x86_64
% 0.09/0.16 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.09/0.16 % Memory : 8046.5625MB
% 0.09/0.16 % OS : Linux 6.8.0-71-generic
% 0.09/0.16 % CPULimit : 300
% 0.09/0.16 % WCLimit : 300
% 0.09/0.16 % DateTime : Mon Sep 28 15:39:27 UTC 2026
% 0.09/0.16 % CPUTime :
% 0.09/0.16 Running run_twee /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.15/0.90 Command-line arguments: --lhs-weight 1 --flip-ordering --normalise-queue-percent 10 --cp-renormalise-threshold 10 --complete-subsets --ground-joining-incomplete-limit 15 --flatten-regeneralise
% 0.15/0.90
% 0.15/0.90 % SZS status Unsatisfiable
% 0.15/0.90
% 0.15/0.90 % SZS output start Proof
% 0.15/0.90 Axiom 1 (axiom_13): r0(e) = true.
% 0.15/0.90 Axiom 2 (axiom_28): k0(e) = true.
% 0.15/0.90 Axiom 3 (ifeq_axiom): ifeq(X, X, Y, Z) = Y.
% 0.15/0.90 Axiom 4 (rule_324): ifeq(l4(X), true, q5(X, X), true) = true.
% 0.15/0.90 Axiom 5 (rule_244): ifeq(n2(X), true, p3(X, X, X), true) = true.
% 0.15/0.90 Axiom 6 (rule_137): ifeq(p1(X, Y, Z), true, n2(Z), true) = true.
% 0.15/0.90 Axiom 7 (rule_277): ifeq(p3(X, Y, Z), true, l4(Z), true) = true.
% 0.15/0.90 Axiom 8 (rule_090): ifeq(k0(e), true, ifeq(r0(e), true, p1(e, e, e), true), true) = true.
% 0.15/0.90
% 0.15/0.90 Goal 1 (prove_this): q5(e, e) = true.
% 0.15/0.90 Proof:
% 0.15/0.90 q5(e, e)
% 0.15/0.90 = { by axiom 3 (ifeq_axiom) R->L }
% 0.15/0.90 ifeq(true, true, q5(e, e), true)
% 0.15/0.90 = { by axiom 7 (rule_277) R->L }
% 0.15/0.90 ifeq(ifeq(p3(e, e, e), true, l4(e), true), true, q5(e, e), true)
% 0.15/0.90 = { by axiom 3 (ifeq_axiom) R->L }
% 0.15/0.90 ifeq(ifeq(ifeq(true, true, p3(e, e, e), true), true, l4(e), true), true, q5(e, e), true)
% 0.15/0.90 = { by axiom 6 (rule_137) R->L }
% 0.15/0.90 ifeq(ifeq(ifeq(ifeq(p1(e, e, e), true, n2(e), true), true, p3(e, e, e), true), true, l4(e), true), true, q5(e, e), true)
% 0.15/0.90 = { by axiom 3 (ifeq_axiom) R->L }
% 0.15/0.90 ifeq(ifeq(ifeq(ifeq(ifeq(true, true, p1(e, e, e), true), true, n2(e), true), true, p3(e, e, e), true), true, l4(e), true), true, q5(e, e), true)
% 0.15/0.90 = { by axiom 1 (axiom_13) R->L }
% 0.15/0.90 ifeq(ifeq(ifeq(ifeq(ifeq(r0(e), true, p1(e, e, e), true), true, n2(e), true), true, p3(e, e, e), true), true, l4(e), true), true, q5(e, e), true)
% 0.15/0.90 = { by axiom 3 (ifeq_axiom) R->L }
% 0.15/0.90 ifeq(ifeq(ifeq(ifeq(ifeq(true, true, ifeq(r0(e), true, p1(e, e, e), true), true), true, n2(e), true), true, p3(e, e, e), true), true, l4(e), true), true, q5(e, e), true)
% 0.15/0.90 = { by axiom 2 (axiom_28) R->L }
% 0.15/0.90 ifeq(ifeq(ifeq(ifeq(ifeq(k0(e), true, ifeq(r0(e), true, p1(e, e, e), true), true), true, n2(e), true), true, p3(e, e, e), true), true, l4(e), true), true, q5(e, e), true)
% 0.15/0.90 = { by axiom 8 (rule_090) }
% 0.15/0.90 ifeq(ifeq(ifeq(ifeq(true, true, n2(e), true), true, p3(e, e, e), true), true, l4(e), true), true, q5(e, e), true)
% 0.15/0.90 = { by axiom 3 (ifeq_axiom) }
% 0.15/0.90 ifeq(ifeq(ifeq(n2(e), true, p3(e, e, e), true), true, l4(e), true), true, q5(e, e), true)
% 0.15/0.90 = { by axiom 5 (rule_244) }
% 0.15/0.90 ifeq(ifeq(true, true, l4(e), true), true, q5(e, e), true)
% 0.15/0.90 = { by axiom 3 (ifeq_axiom) }
% 0.15/0.90 ifeq(l4(e), true, q5(e, e), true)
% 0.15/0.90 = { by axiom 4 (rule_324) }
% 0.15/0.90 true
% 0.15/0.90 % SZS output end Proof
% 0.15/0.90
% 0.15/0.90 RESULT: Unsatisfiable (the axioms are contradictory).
%------------------------------------------------------------------------------