%------------------------------------------------------------------------------
% File : Twee---2.7
% Problem : SYN188-1 : TPTP v9.3.1. Released v1.1.0.
% Transfm : none
% Format : tptp:raw
% Command : run_twee /export/starexec/sandbox2/benchmark/theBenchmark.p
% Computer : n003.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8046.5625MB
% OS : Linux 6.8.0-71-generic
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Tue Sep 29 01:47:16 PM UTC 2026
% Result : Unsatisfiable 4.89s 0.98s
% Output : Proof 4.89s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.02 % Problem : SYN188-1 : TPTP v9.3.1. Released v1.1.0.
% 0.00/0.04 % Command : run_twee /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.12/0.17 % Computer : n003.cluster.edu
% 0.12/0.17 % Model : x86_64 x86_64
% 0.12/0.17 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.17 % Memory : 8046.5625MB
% 0.12/0.17 % OS : Linux 6.8.0-71-generic
% 0.12/0.17 % CPULimit : 300
% 0.12/0.17 % WCLimit : 300
% 0.12/0.17 % DateTime : Mon Sep 28 15:39:42 UTC 2026
% 0.12/0.18 % CPUTime :
% 0.12/0.18 Running run_twee /export/starexec/sandbox2/benchmark/theBenchmark.p
% 4.89/0.98 Command-line arguments: --lhs-weight 9 --flip-ordering --complete-subsets --normalise-queue-percent 10 --cp-renormalise-threshold 10
% 4.89/0.98
% 4.89/0.98 % SZS status Unsatisfiable
% 4.89/0.98
% 4.89/0.98 % SZS output start Proof
% 4.89/0.98 Axiom 1 (axiom_1): s0(d) = true.
% 4.89/0.98 Axiom 2 (axiom_17): q0(X, d) = true.
% 4.89/0.98 Axiom 3 (axiom_19): m0(X, d, Y) = true.
% 4.89/0.98 Axiom 4 (ifeq_axiom): ifeq(X, X, Y, Z) = Y.
% 4.89/0.98 Axiom 5 (rule_122): ifeq(m0(X, Y, X), true, q1(X, X, X), true) = true.
% 4.89/0.98 Axiom 6 (rule_124): ifeq(q1(d, X, d), true, ifeq(q0(Y, X), true, ifeq(s0(d), true, r1(Y), true), true), true) = true.
% 4.89/0.98
% 4.89/0.98 Goal 1 (prove_this): r1(e) = true.
% 4.89/0.98 Proof:
% 4.89/0.98 r1(e)
% 4.89/0.98 = { by axiom 4 (ifeq_axiom) R->L }
% 4.89/0.98 ifeq(true, true, r1(e), true)
% 4.89/0.98 = { by axiom 2 (axiom_17) R->L }
% 4.89/0.98 ifeq(q0(e, d), true, r1(e), true)
% 4.89/0.98 = { by axiom 4 (ifeq_axiom) R->L }
% 4.89/0.98 ifeq(true, true, ifeq(q0(e, d), true, r1(e), true), true)
% 4.89/0.98 = { by axiom 5 (rule_122) R->L }
% 4.89/0.98 ifeq(ifeq(m0(d, d, d), true, q1(d, d, d), true), true, ifeq(q0(e, d), true, r1(e), true), true)
% 4.89/0.98 = { by axiom 3 (axiom_19) }
% 4.89/0.98 ifeq(ifeq(true, true, q1(d, d, d), true), true, ifeq(q0(e, d), true, r1(e), true), true)
% 4.89/0.98 = { by axiom 4 (ifeq_axiom) }
% 4.89/0.98 ifeq(q1(d, d, d), true, ifeq(q0(e, d), true, r1(e), true), true)
% 4.89/0.98 = { by axiom 4 (ifeq_axiom) R->L }
% 4.89/0.98 ifeq(q1(d, d, d), true, ifeq(q0(e, d), true, ifeq(true, true, r1(e), true), true), true)
% 4.89/0.98 = { by axiom 1 (axiom_1) R->L }
% 4.89/0.98 ifeq(q1(d, d, d), true, ifeq(q0(e, d), true, ifeq(s0(d), true, r1(e), true), true), true)
% 4.89/0.98 = { by axiom 6 (rule_124) }
% 4.89/0.98 true
% 4.89/0.98 % SZS output end Proof
% 4.89/0.98
% 4.89/0.98 RESULT: Unsatisfiable (the axioms are contradictory).
%------------------------------------------------------------------------------