%------------------------------------------------------------------------------
% File : Twee---2.7
% Problem : SYN189-1 : TPTP v9.3.1. Released v1.1.0.
% Transfm : none
% Format : tptp:raw
% Command : run_twee /export/starexec/sandbox/benchmark/theBenchmark.p
% Computer : n008.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8046.5625MB
% OS : Linux 6.8.0-71-generic
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Tue Sep 29 01:47:16 PM UTC 2026
% Result : Unsatisfiable 6.17s 1.05s
% Output : Proof 6.17s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.02 % Problem : SYN189-1 : TPTP v9.3.1. Released v1.1.0.
% 0.00/0.04 % Command : run_twee /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.08/0.16 % Computer : n008.cluster.edu
% 0.08/0.16 % Model : x86_64 x86_64
% 0.08/0.16 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.08/0.16 % Memory : 8046.5625MB
% 0.08/0.16 % OS : Linux 6.8.0-71-generic
% 0.08/0.16 % CPULimit : 300
% 0.08/0.16 % WCLimit : 300
% 0.08/0.16 % DateTime : Mon Sep 28 15:38:39 UTC 2026
% 0.08/0.16 % CPUTime :
% 0.08/0.16 Running run_twee /export/starexec/sandbox/benchmark/theBenchmark.p
% 6.17/1.05 Command-line arguments: --lhs-weight 1 --flip-ordering --normalise-queue-percent 10 --cp-renormalise-threshold 10 --complete-subsets --ground-joining-incomplete-limit 15 --flatten-regeneralise
% 6.17/1.05
% 6.17/1.05 % SZS status Unsatisfiable
% 6.17/1.05
% 6.17/1.05 % SZS output start Proof
% 6.17/1.05 Axiom 1 (axiom_1): s0(d) = true.
% 6.17/1.05 Axiom 2 (axiom_24): l0(c) = true.
% 6.17/1.05 Axiom 3 (axiom_17): q0(X, d) = true.
% 6.17/1.05 Axiom 4 (axiom_19): m0(X, d, Y) = true.
% 6.17/1.05 Axiom 5 (ifeq_axiom): ifeq(X, X, Y, Z) = Y.
% 6.17/1.05 Axiom 6 (rule_122): ifeq(m0(X, Y, X), true, q1(X, X, X), true) = true.
% 6.17/1.05 Axiom 7 (rule_188): ifeq(r1(X), true, ifeq(l0(X), true, r2(X), true), true) = true.
% 6.17/1.05 Axiom 8 (rule_124): ifeq(q1(d, X, d), true, ifeq(q0(Y, X), true, ifeq(s0(d), true, r1(Y), true), true), true) = true.
% 6.17/1.05
% 6.17/1.05 Goal 1 (prove_this): r2(c) = true.
% 6.17/1.05 Proof:
% 6.17/1.05 r2(c)
% 6.17/1.05 = { by axiom 5 (ifeq_axiom) R->L }
% 6.17/1.05 ifeq(true, true, r2(c), true)
% 6.17/1.05 = { by axiom 5 (ifeq_axiom) R->L }
% 6.17/1.05 ifeq(true, true, ifeq(true, true, r2(c), true), true)
% 6.17/1.05 = { by axiom 8 (rule_124) R->L }
% 6.17/1.05 ifeq(ifeq(q1(d, d, d), true, ifeq(q0(c, d), true, ifeq(s0(d), true, r1(c), true), true), true), true, ifeq(true, true, r2(c), true), true)
% 6.17/1.05 = { by axiom 1 (axiom_1) }
% 6.17/1.05 ifeq(ifeq(q1(d, d, d), true, ifeq(q0(c, d), true, ifeq(true, true, r1(c), true), true), true), true, ifeq(true, true, r2(c), true), true)
% 6.17/1.05 = { by axiom 5 (ifeq_axiom) }
% 6.17/1.05 ifeq(ifeq(q1(d, d, d), true, ifeq(q0(c, d), true, r1(c), true), true), true, ifeq(true, true, r2(c), true), true)
% 6.17/1.05 = { by axiom 5 (ifeq_axiom) R->L }
% 6.17/1.05 ifeq(ifeq(ifeq(true, true, q1(d, d, d), true), true, ifeq(q0(c, d), true, r1(c), true), true), true, ifeq(true, true, r2(c), true), true)
% 6.17/1.05 = { by axiom 4 (axiom_19) R->L }
% 6.17/1.05 ifeq(ifeq(ifeq(m0(d, d, d), true, q1(d, d, d), true), true, ifeq(q0(c, d), true, r1(c), true), true), true, ifeq(true, true, r2(c), true), true)
% 6.17/1.05 = { by axiom 6 (rule_122) }
% 6.17/1.05 ifeq(ifeq(true, true, ifeq(q0(c, d), true, r1(c), true), true), true, ifeq(true, true, r2(c), true), true)
% 6.17/1.05 = { by axiom 5 (ifeq_axiom) }
% 6.17/1.05 ifeq(ifeq(q0(c, d), true, r1(c), true), true, ifeq(true, true, r2(c), true), true)
% 6.17/1.05 = { by axiom 3 (axiom_17) }
% 6.17/1.05 ifeq(ifeq(true, true, r1(c), true), true, ifeq(true, true, r2(c), true), true)
% 6.17/1.05 = { by axiom 5 (ifeq_axiom) }
% 6.17/1.05 ifeq(r1(c), true, ifeq(true, true, r2(c), true), true)
% 6.17/1.05 = { by axiom 2 (axiom_24) R->L }
% 6.17/1.05 ifeq(r1(c), true, ifeq(l0(c), true, r2(c), true), true)
% 6.17/1.05 = { by axiom 7 (rule_188) }
% 6.17/1.05 true
% 6.17/1.05 % SZS output end Proof
% 6.17/1.05
% 6.17/1.05 RESULT: Unsatisfiable (the axioms are contradictory).
%------------------------------------------------------------------------------