%------------------------------------------------------------------------------
% File : Twee---2.7
% Problem : SYN243-1 : TPTP v9.3.1. Released v1.1.0.
% Transfm : none
% Format : tptp:raw
% Command : run_twee /export/starexec/sandbox/benchmark/theBenchmark.p
% Computer : n006.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8046.5625MB
% OS : Linux 6.8.0-71-generic
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Tue Sep 29 01:47:23 PM UTC 2026
% Result : Unsatisfiable 3.70s 0.72s
% Output : Proof 3.70s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.02 % Problem : SYN243-1 : TPTP v9.3.1. Released v1.1.0.
% 0.00/0.03 % Command : run_twee /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.07/0.17 % Computer : n006.cluster.edu
% 0.07/0.17 % Model : x86_64 x86_64
% 0.07/0.17 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.07/0.17 % Memory : 8046.5625MB
% 0.07/0.17 % OS : Linux 6.8.0-71-generic
% 0.07/0.17 % CPULimit : 300
% 0.07/0.17 % WCLimit : 300
% 0.07/0.17 % DateTime : Mon Sep 28 15:38:55 UTC 2026
% 0.07/0.17 % CPUTime :
% 0.07/0.17 Running run_twee /export/starexec/sandbox/benchmark/theBenchmark.p
% 3.70/0.72 Command-line arguments: --flatten-regeneralise
% 3.70/0.72
% 3.70/0.72 % SZS status Unsatisfiable
% 3.70/0.72
% 3.70/0.72 % SZS output start Proof
% 3.70/0.72 Axiom 1 (axiom_20): l0(a) = true.
% 3.70/0.72 Axiom 2 (axiom_19): m0(X, d, Y) = true.
% 3.70/0.72 Axiom 3 (ifeq_axiom): ifeq(X, X, Y, Z) = Y.
% 3.70/0.72 Axiom 4 (rule_015): ifeq(l0(X), true, ifeq(m0(Y, Y, Z), true, m1(Z, Y, Y), true), true) = true.
% 3.70/0.72
% 3.70/0.72 Goal 1 (prove_this): m1(a, d, d) = true.
% 3.70/0.72 Proof:
% 3.70/0.72 m1(a, d, d)
% 3.70/0.72 = { by axiom 3 (ifeq_axiom) R->L }
% 3.70/0.72 ifeq(true, true, m1(a, d, d), true)
% 3.70/0.72 = { by axiom 1 (axiom_20) R->L }
% 3.70/0.72 ifeq(l0(a), true, m1(a, d, d), true)
% 3.70/0.72 = { by axiom 3 (ifeq_axiom) R->L }
% 3.70/0.72 ifeq(l0(a), true, ifeq(true, true, m1(a, d, d), true), true)
% 3.70/0.72 = { by axiom 2 (axiom_19) R->L }
% 3.70/0.72 ifeq(l0(a), true, ifeq(m0(d, d, a), true, m1(a, d, d), true), true)
% 3.70/0.72 = { by axiom 4 (rule_015) }
% 3.70/0.72 true
% 3.70/0.72 % SZS output end Proof
% 3.70/0.72
% 3.70/0.72 RESULT: Unsatisfiable (the axioms are contradictory).
%------------------------------------------------------------------------------