%------------------------------------------------------------------------------
% File : Twee---2.7
% Problem : SYN255-1 : TPTP v9.3.1. Released v1.1.0.
% Transfm : none
% Format : tptp:raw
% Command : run_twee /export/starexec/sandbox/benchmark/theBenchmark.p
% Computer : n008.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8046.5625MB
% OS : Linux 6.8.0-71-generic
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Tue Sep 29 01:47:24 PM UTC 2026
% Result : Unsatisfiable 4.60s 0.83s
% Output : Proof 4.60s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.03 % Problem : SYN255-1 : TPTP v9.3.1. Released v1.1.0.
% 0.00/0.05 % Command : run_twee /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.08/0.17 % Computer : n008.cluster.edu
% 0.08/0.17 % Model : x86_64 x86_64
% 0.08/0.17 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.08/0.17 % Memory : 8046.5625MB
% 0.08/0.17 % OS : Linux 6.8.0-71-generic
% 0.08/0.18 % CPULimit : 300
% 0.08/0.18 % WCLimit : 300
% 0.08/0.18 % DateTime : Mon Sep 28 15:39:39 UTC 2026
% 0.08/0.18 % CPUTime :
% 0.08/0.18 Running run_twee /export/starexec/sandbox/benchmark/theBenchmark.p
% 4.60/0.83 Command-line arguments: --lhs-weight 9 --flip-ordering --complete-subsets --normalise-queue-percent 10 --cp-renormalise-threshold 10
% 4.60/0.83
% 4.60/0.83 % SZS status Unsatisfiable
% 4.60/0.83
% 4.60/0.83 % SZS output start Proof
% 4.60/0.83 Axiom 1 (axiom_20): l0(a) = true.
% 4.60/0.83 Axiom 2 (ifeq_axiom): ifeq(X, X, Y, Z) = Y.
% 4.60/0.83 Axiom 3 (rule_088): ifeq(l0(a), true, p1(a, a, a), true) = true.
% 4.60/0.83 Axiom 4 (rule_137): ifeq(p1(X, Y, Z), true, n2(Z), true) = true.
% 4.60/0.83
% 4.60/0.83 Goal 1 (prove_this): n2(a) = true.
% 4.60/0.83 Proof:
% 4.60/0.83 n2(a)
% 4.60/0.83 = { by axiom 2 (ifeq_axiom) R->L }
% 4.60/0.83 ifeq(true, true, n2(a), true)
% 4.60/0.83 = { by axiom 3 (rule_088) R->L }
% 4.60/0.83 ifeq(ifeq(l0(a), true, p1(a, a, a), true), true, n2(a), true)
% 4.60/0.83 = { by axiom 1 (axiom_20) }
% 4.60/0.83 ifeq(ifeq(true, true, p1(a, a, a), true), true, n2(a), true)
% 4.60/0.83 = { by axiom 2 (ifeq_axiom) }
% 4.60/0.83 ifeq(p1(a, a, a), true, n2(a), true)
% 4.60/0.83 = { by axiom 4 (rule_137) }
% 4.60/0.83 true
% 4.60/0.83 % SZS output end Proof
% 4.60/0.83
% 4.60/0.83 RESULT: Unsatisfiable (the axioms are contradictory).
%------------------------------------------------------------------------------