%------------------------------------------------------------------------------
% File : Twee---2.7
% Problem : SYN260-1 : TPTP v9.3.1. Released v1.1.0.
% Transfm : none
% Format : tptp:raw
% Command : run_twee /export/starexec/sandbox2/benchmark/theBenchmark.p
% Computer : n009.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8046.5625MB
% OS : Linux 6.8.0-71-generic
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Tue Sep 29 01:47:25 PM UTC 2026
% Result : Unsatisfiable 3.62s 0.70s
% Output : Proof 3.62s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.03 % Problem : SYN260-1 : TPTP v9.3.1. Released v1.1.0.
% 0.00/0.04 % Command : run_twee /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.07/0.18 % Computer : n009.cluster.edu
% 0.07/0.18 % Model : x86_64 x86_64
% 0.07/0.18 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.07/0.18 % Memory : 8046.5625MB
% 0.07/0.18 % OS : Linux 6.8.0-71-generic
% 0.07/0.18 % CPULimit : 300
% 0.07/0.18 % WCLimit : 300
% 0.07/0.18 % DateTime : Mon Sep 28 15:39:00 UTC 2026
% 0.07/0.18 % CPUTime :
% 0.07/0.18 Running run_twee /export/starexec/sandbox2/benchmark/theBenchmark.p
% 3.62/0.70 Command-line arguments: --lhs-weight 1 --flip-ordering --normalise-queue-percent 10 --cp-renormalise-threshold 10 --complete-subsets --ground-joining-incomplete-limit 15 --flatten-every 2
% 3.62/0.70
% 3.62/0.70 % SZS status Unsatisfiable
% 3.62/0.70
% 3.62/0.70 % SZS output start Proof
% 3.62/0.70 Axiom 1 (axiom_14): p0(b, X) = true.
% 3.62/0.70 Axiom 2 (ifeq_axiom): ifeq(X, X, Y, Z) = Y.
% 3.62/0.70 Axiom 3 (rule_085): ifeq(p0(X, Y), true, p1(Y, Y, Y), true) = true.
% 3.62/0.70
% 3.62/0.70 Goal 1 (prove_this): p1(X, d, d) = true.
% 3.62/0.70 The goal is true when:
% 3.62/0.70 X = d
% 3.62/0.70
% 3.62/0.70 Proof:
% 3.62/0.70 p1(d, d, d)
% 3.62/0.70 = { by axiom 2 (ifeq_axiom) R->L }
% 3.62/0.70 ifeq(true, true, p1(d, d, d), true)
% 3.62/0.70 = { by axiom 1 (axiom_14) R->L }
% 3.62/0.70 ifeq(p0(b, d), true, p1(d, d, d), true)
% 3.62/0.70 = { by axiom 3 (rule_085) }
% 3.62/0.70 true
% 3.62/0.70 % SZS output end Proof
% 3.62/0.70
% 3.62/0.70 RESULT: Unsatisfiable (the axioms are contradictory).
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