%------------------------------------------------------------------------------
% File : Twee---2.7
% Problem : SYN284-1 : TPTP v9.3.1. Released v1.1.0.
% Transfm : none
% Format : tptp:raw
% Command : run_twee /export/starexec/sandbox2/benchmark/theBenchmark.p
% Computer : n011.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8046.5625MB
% OS : Linux 6.8.0-71-generic
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Tue Sep 29 01:47:28 PM UTC 2026
% Result : Unsatisfiable 6.62s 1.17s
% Output : Proof 6.62s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.03 % Problem : SYN284-1 : TPTP v9.3.1. Released v1.1.0.
% 0.00/0.04 % Command : run_twee /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.09/0.18 % Computer : n011.cluster.edu
% 0.09/0.18 % Model : x86_64 x86_64
% 0.09/0.18 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.09/0.18 % Memory : 8046.5625MB
% 0.09/0.18 % OS : Linux 6.8.0-71-generic
% 0.09/0.18 % CPULimit : 300
% 0.09/0.18 % WCLimit : 300
% 0.09/0.18 % DateTime : Mon Sep 28 15:40:45 UTC 2026
% 0.09/0.18 % CPUTime :
% 0.09/0.18 Running run_twee /export/starexec/sandbox2/benchmark/theBenchmark.p
% 6.62/1.17 Command-line arguments: --lhs-weight 9 --flip-ordering --complete-subsets --normalise-queue-percent 10 --cp-renormalise-threshold 10
% 6.62/1.17
% 6.62/1.17 % SZS status Unsatisfiable
% 6.62/1.17
% 6.62/1.17 % SZS output start Proof
% 6.62/1.17 Axiom 1 (axiom_14): p0(b, X) = true.
% 6.62/1.17 Axiom 2 (axiom_26): n0(d, c) = true.
% 6.62/1.17 Axiom 3 (ifeq_axiom): ifeq(X, X, Y, Z) = Y.
% 6.62/1.17 Axiom 4 (rule_092): ifeq(p0(X, Y), true, ifeq(n0(Z, W), true, q1(Y, W, Y), true), true) = true.
% 6.62/1.17
% 6.62/1.17 Goal 1 (prove_this): q1(a, c, a) = true.
% 6.62/1.17 Proof:
% 6.62/1.17 q1(a, c, a)
% 6.62/1.17 = { by axiom 3 (ifeq_axiom) R->L }
% 6.62/1.17 ifeq(true, true, q1(a, c, a), true)
% 6.62/1.17 = { by axiom 2 (axiom_26) R->L }
% 6.62/1.17 ifeq(n0(d, c), true, q1(a, c, a), true)
% 6.62/1.17 = { by axiom 3 (ifeq_axiom) R->L }
% 6.62/1.17 ifeq(true, true, ifeq(n0(d, c), true, q1(a, c, a), true), true)
% 6.62/1.17 = { by axiom 1 (axiom_14) R->L }
% 6.62/1.17 ifeq(p0(b, a), true, ifeq(n0(d, c), true, q1(a, c, a), true), true)
% 6.62/1.17 = { by axiom 4 (rule_092) }
% 6.62/1.17 true
% 6.62/1.17 % SZS output end Proof
% 6.62/1.17
% 6.62/1.17 RESULT: Unsatisfiable (the axioms are contradictory).
%------------------------------------------------------------------------------