%------------------------------------------------------------------------------
% File : Twee---2.7
% Problem : SYN287-1 : TPTP v9.3.1. Released v1.1.0.
% Transfm : none
% Format : tptp:raw
% Command : run_twee /export/starexec/sandbox2/benchmark/theBenchmark.p
% Computer : n016.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8046.5625MB
% OS : Linux 6.8.0-71-generic
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Tue Sep 29 01:47:28 PM UTC 2026
% Result : Unsatisfiable 5.09s 0.95s
% Output : Proof 5.09s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.03 % Problem : SYN287-1 : TPTP v9.3.1. Released v1.1.0.
% 0.00/0.04 % Command : run_twee /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.09/0.18 % Computer : n016.cluster.edu
% 0.09/0.18 % Model : x86_64 x86_64
% 0.09/0.18 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.09/0.18 % Memory : 8046.5625MB
% 0.09/0.18 % OS : Linux 6.8.0-71-generic
% 0.09/0.18 % CPULimit : 300
% 0.09/0.18 % WCLimit : 300
% 0.09/0.18 % DateTime : Mon Sep 28 15:45:33 UTC 2026
% 0.09/0.18 % CPUTime :
% 0.09/0.18 Running run_twee /export/starexec/sandbox2/benchmark/theBenchmark.p
% 5.09/0.95 Command-line arguments: --flatten-regeneralise
% 5.09/0.95
% 5.09/0.95 % SZS status Unsatisfiable
% 5.09/0.95
% 5.09/0.95 % SZS output start Proof
% 5.09/0.95 Axiom 1 (axiom_19): m0(X, d, Y) = true.
% 5.09/0.95 Axiom 2 (ifeq_axiom): ifeq(X, X, Y, Z) = Y.
% 5.09/0.95 Axiom 3 (rule_122): ifeq(m0(X, Y, X), true, q1(X, X, X), true) = true.
% 5.09/0.95
% 5.09/0.95 Goal 1 (prove_this): q1(b, X, Y) = true.
% 5.09/0.95 The goal is true when:
% 5.09/0.95 X = b
% 5.09/0.95 Y = b
% 5.09/0.95
% 5.09/0.95 Proof:
% 5.09/0.95 q1(b, b, b)
% 5.09/0.95 = { by axiom 2 (ifeq_axiom) R->L }
% 5.09/0.95 ifeq(true, true, q1(b, b, b), true)
% 5.09/0.95 = { by axiom 1 (axiom_19) R->L }
% 5.09/0.95 ifeq(m0(b, d, b), true, q1(b, b, b), true)
% 5.09/0.95 = { by axiom 3 (rule_122) }
% 5.09/0.95 true
% 5.09/0.95 % SZS output end Proof
% 5.09/0.95
% 5.09/0.95 RESULT: Unsatisfiable (the axioms are contradictory).
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