↑ Up

Twee---2.7.UNS-Prf.s

View TPTP
Problem
Process solution in
SystemOnTSTP
Download .tgz
%------------------------------------------------------------------------------
% File     : Twee---2.7
% Problem  : SYN289-1 : TPTP v9.3.1. Released v1.1.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : run_twee /export/starexec/sandbox2/benchmark/theBenchmark.p

% Computer : n012.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8046.5625MB
% OS       : Linux 6.8.0-71-generic
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Tue Sep 29 01:47:28 PM UTC 2026

% Result   : Unsatisfiable 4.39s 0.72s
% Output   : Proof 4.39s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.01  % Problem  : SYN289-1 : TPTP v9.3.1. Released v1.1.0.
% 0.00/0.02  % Command  : run_twee /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.00/0.10  % Computer : n012.cluster.edu
% 0.00/0.10  % Model    : x86_64 x86_64
% 0.00/0.10  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.00/0.10  % Memory   : 8046.5625MB
% 0.00/0.10  % OS       : Linux 6.8.0-71-generic
% 0.00/0.10  % CPULimit : 300
% 0.00/0.10  % WCLimit  : 300
% 0.00/0.10  % DateTime : Mon Sep 28 15:40:04 UTC 2026
% 0.00/0.10  % CPUTime  : 
% 0.00/0.10  Running run_twee /export/starexec/sandbox2/benchmark/theBenchmark.p
% 4.39/0.72  Command-line arguments: --lhs-weight 1 --flip-ordering --normalise-queue-percent 10 --cp-renormalise-threshold 10 --complete-subsets --ground-joining-incomplete-limit 15 --flatten-every 2
% 4.39/0.72  
% 4.39/0.72  % SZS status Unsatisfiable
% 4.39/0.72  
% 4.39/0.72  % SZS output start Proof
% 4.39/0.72  Axiom 1 (axiom_14): p0(b, X) = true.
% 4.39/0.72  Axiom 2 (axiom_34): n0(c, d) = true.
% 4.39/0.72  Axiom 3 (ifeq_axiom): ifeq(X, X, Y, Z) = Y.
% 4.39/0.72  Axiom 4 (rule_092): ifeq(p0(X, Y), true, ifeq(n0(Z, W), true, q1(Y, W, Y), true), true) = true.
% 4.39/0.72  
% 4.39/0.72  Goal 1 (prove_this): q1(b, d, b) = true.
% 4.39/0.72  Proof:
% 4.39/0.72    q1(b, d, b)
% 4.39/0.72  = { by axiom 3 (ifeq_axiom) R->L }
% 4.39/0.72    ifeq(true, true, q1(b, d, b), true)
% 4.39/0.72  = { by axiom 2 (axiom_34) R->L }
% 4.39/0.72    ifeq(n0(c, d), true, q1(b, d, b), true)
% 4.39/0.72  = { by axiom 3 (ifeq_axiom) R->L }
% 4.39/0.72    ifeq(true, true, ifeq(n0(c, d), true, q1(b, d, b), true), true)
% 4.39/0.72  = { by axiom 1 (axiom_14) R->L }
% 4.39/0.72    ifeq(p0(b, b), true, ifeq(n0(c, d), true, q1(b, d, b), true), true)
% 4.39/0.72  = { by axiom 4 (rule_092) }
% 4.39/0.72    true
% 4.39/0.72  % SZS output end Proof
% 4.39/0.72  
% 4.39/0.72  RESULT: Unsatisfiable (the axioms are contradictory).
%------------------------------------------------------------------------------