%------------------------------------------------------------------------------
% File : Twee---2.7
% Problem : SYN296-1 : TPTP v9.3.1. Released v1.1.0.
% Transfm : none
% Format : tptp:raw
% Command : run_twee /export/starexec/sandbox/benchmark/theBenchmark.p
% Computer : n016.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8046.5625MB
% OS : Linux 6.8.0-71-generic
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Tue Sep 29 01:47:29 PM UTC 2026
% Result : Unsatisfiable 6.86s 1.12s
% Output : Proof 6.86s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.03 % Problem : SYN296-1 : TPTP v9.3.1. Released v1.1.0.
% 0.00/0.04 % Command : run_twee /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.08/0.17 % Computer : n016.cluster.edu
% 0.08/0.17 % Model : x86_64 x86_64
% 0.08/0.17 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.08/0.17 % Memory : 8046.5625MB
% 0.08/0.17 % OS : Linux 6.8.0-71-generic
% 0.08/0.17 % CPULimit : 300
% 0.08/0.17 % WCLimit : 300
% 0.08/0.17 % DateTime : Mon Sep 28 15:45:18 UTC 2026
% 0.08/0.18 % CPUTime :
% 0.08/0.18 Running run_twee /export/starexec/sandbox/benchmark/theBenchmark.p
% 6.86/1.12 Command-line arguments: --lhs-weight 1 --flip-ordering --normalise-queue-percent 10 --cp-renormalise-threshold 10 --complete-subsets --ground-joining-incomplete-limit 15 --flatten-regeneralise
% 6.86/1.12
% 6.86/1.12 % SZS status Unsatisfiable
% 6.86/1.12
% 6.86/1.12 % SZS output start Proof
% 6.86/1.12 Axiom 1 (axiom_14): p0(b, X) = true.
% 6.86/1.12 Axiom 2 (axiom_11): n0(e, b) = true.
% 6.86/1.12 Axiom 3 (ifeq_axiom): ifeq(X, X, Y, Z) = Y.
% 6.86/1.12 Axiom 4 (rule_092): ifeq(p0(X, Y), true, ifeq(n0(Z, W), true, q1(Y, W, Y), true), true) = true.
% 6.86/1.12
% 6.86/1.12 Goal 1 (prove_this): q1(e, b, e) = true.
% 6.86/1.12 Proof:
% 6.86/1.12 q1(e, b, e)
% 6.86/1.12 = { by axiom 3 (ifeq_axiom) R->L }
% 6.86/1.12 ifeq(true, true, q1(e, b, e), true)
% 6.86/1.12 = { by axiom 2 (axiom_11) R->L }
% 6.86/1.12 ifeq(n0(e, b), true, q1(e, b, e), true)
% 6.86/1.12 = { by axiom 3 (ifeq_axiom) R->L }
% 6.86/1.12 ifeq(true, true, ifeq(n0(e, b), true, q1(e, b, e), true), true)
% 6.86/1.12 = { by axiom 1 (axiom_14) R->L }
% 6.86/1.12 ifeq(p0(b, e), true, ifeq(n0(e, b), true, q1(e, b, e), true), true)
% 6.86/1.12 = { by axiom 4 (rule_092) }
% 6.86/1.12 true
% 6.86/1.12 % SZS output end Proof
% 6.86/1.12
% 6.86/1.12 RESULT: Unsatisfiable (the axioms are contradictory).
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