↑ Up

Duper---1.0.THM-Prf.s

View TPTP
Problem
Process solution in
SystemOnTSTP
Download .tgz
%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : SYN338+1 : TPTP v9.2.0. Released v2.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n021.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Oct  3 08:07:26 PM UTC 2025

% Result   : Theorem 4.76s 4.96s
% Output   : Proof 4.76s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.12/0.14  % Problem    : SYN338+1 : TPTP v9.2.0. Released v2.0.0.
% 0.12/0.15  % Command    : duper %s
% 0.14/0.36  % Computer : n021.cluster.edu
% 0.14/0.36  % Model    : x86_64 x86_64
% 0.14/0.36  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.36  % Memory   : 8042.1875MB
% 0.14/0.36  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.36  % CPULimit   : 300
% 0.14/0.36  % WCLimit    : 300
% 0.14/0.36  % DateTime   : Thu Oct  2 15:21:08 EDT 2025
% 0.14/0.36  % CPUTime    : 
% 4.76/4.96  SZS status Theorem for theBenchmark.p
% 4.76/4.96  SZS output start Proof for theBenchmark.p
% 4.76/4.96  Clause #0 (by assumption #[]): Eq (Not (Exists fun X => ∀ (Y : Iota), Exists fun Z => big_f X Y → big_f Z X → big_f Y Y)) True
% 4.76/4.96  Clause #1 (by clausification #[0]): Eq (Exists fun X => ∀ (Y : Iota), Exists fun Z => big_f X Y → big_f Z X → big_f Y Y) False
% 4.76/4.96  Clause #2 (by clausification #[1]): ∀ (a : Iota), Eq (∀ (Y : Iota), Exists fun Z => big_f a Y → big_f Z a → big_f Y Y) False
% 4.76/4.96  Clause #3 (by clausification #[2]): ∀ (a a_1 : Iota),
% 4.76/4.96    Eq (Not (Exists fun Z => big_f a (skS.0 0 a a_1) → big_f Z a → big_f (skS.0 0 a a_1) (skS.0 0 a a_1))) True
% 4.76/4.96  Clause #4 (by clausification #[3]): ∀ (a a_1 : Iota), Eq (Exists fun Z => big_f a (skS.0 0 a a_1) → big_f Z a → big_f (skS.0 0 a a_1) (skS.0 0 a a_1)) False
% 4.76/4.96  Clause #5 (by clausification #[4]): ∀ (a a_1 a_2 : Iota), Eq (big_f a (skS.0 0 a a_1) → big_f a_2 a → big_f (skS.0 0 a a_1) (skS.0 0 a a_1)) False
% 4.76/4.96  Clause #7 (by clausification #[5]): ∀ (a a_1 a_2 : Iota), Eq (big_f a a_1 → big_f (skS.0 0 a_1 a_2) (skS.0 0 a_1 a_2)) False
% 4.76/4.96  Clause #8 (by clausification #[7]): ∀ (a a_1 : Iota), Eq (big_f a a_1) True
% 4.76/4.96  Clause #9 (by clausification #[7]): ∀ (a a_1 : Iota), Eq (big_f (skS.0 0 a a_1) (skS.0 0 a a_1)) False
% 4.76/4.96  Clause #10 (by superposition #[9, 8]): Eq False True
% 4.76/4.96  Clause #11 (by clausification #[10]): False
% 4.76/4.96  SZS output end Proof for theBenchmark.p
%------------------------------------------------------------------------------