%------------------------------------------------------------------------------ % File : Duper---1.0 % Problem : SYN343+1 : TPTP v9.2.0. Released v2.0.0. % Transfm : none % Format : tptp:raw % Command : duper %s % Computer : n014.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 300s % DateTime : Fri Oct 3 08:07:26 PM UTC 2025 % Result : Theorem 5.13s 5.38s % Output : Proof 5.13s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.06/0.12 % Problem : SYN343+1 : TPTP v9.2.0. Released v2.0.0. % 0.06/0.13 % Command : duper %s % 0.13/0.34 % Computer : n014.cluster.edu % 0.13/0.34 % Model : x86_64 x86_64 % 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.13/0.34 % Memory : 8042.1875MB % 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64 % 0.13/0.34 % CPULimit : 300 % 0.13/0.34 % WCLimit : 300 % 0.13/0.34 % DateTime : Thu Oct 2 15:28:08 EDT 2025 % 0.13/0.35 % CPUTime : % 5.13/5.38 SZS status Theorem for theBenchmark.p % 5.13/5.38 SZS output start Proof for theBenchmark.p % 5.13/5.38 Clause #0 (by assumption #[]): Eq % 5.13/5.38 (Not % 5.13/5.38 (Exists fun X => % 5.13/5.38 Exists fun Y1 => % 5.13/5.38 Exists fun Y2 => ∀ (Z : Iota), ((big_f X Y1 → big_f Z X) → big_f X X) → And (big_f X X) (big_f Y1 Y2))) % 5.13/5.38 True % 5.13/5.38 Clause #1 (by clausification #[0]): Eq % 5.13/5.38 (Exists fun X => % 5.13/5.38 Exists fun Y1 => % 5.13/5.38 Exists fun Y2 => ∀ (Z : Iota), ((big_f X Y1 → big_f Z X) → big_f X X) → And (big_f X X) (big_f Y1 Y2)) % 5.13/5.38 False % 5.13/5.38 Clause #2 (by clausification #[1]): ∀ (a : Iota), % 5.13/5.38 Eq % 5.13/5.38 (Exists fun Y1 => % 5.13/5.38 Exists fun Y2 => ∀ (Z : Iota), ((big_f a Y1 → big_f Z a) → big_f a a) → And (big_f a a) (big_f Y1 Y2)) % 5.13/5.38 False % 5.13/5.38 Clause #3 (by clausification #[2]): ∀ (a a_1 : Iota), % 5.13/5.38 Eq (Exists fun Y2 => ∀ (Z : Iota), ((big_f a a_1 → big_f Z a) → big_f a a) → And (big_f a a) (big_f a_1 Y2)) False % 5.13/5.38 Clause #4 (by clausification #[3]): ∀ (a a_1 a_2 : Iota), Eq (∀ (Z : Iota), ((big_f a a_1 → big_f Z a) → big_f a a) → And (big_f a a) (big_f a_1 a_2)) False % 5.13/5.38 Clause #5 (by clausification #[4]): ∀ (a a_1 a_2 a_3 : Iota), % 5.13/5.38 Eq (Not (((big_f a a_1 → big_f (skS.0 0 a a_1 a_2 a_3) a) → big_f a a) → And (big_f a a) (big_f a_1 a_2))) True % 5.13/5.38 Clause #6 (by clausification #[5]): ∀ (a a_1 a_2 a_3 : Iota), % 5.13/5.38 Eq (((big_f a a_1 → big_f (skS.0 0 a a_1 a_2 a_3) a) → big_f a a) → And (big_f a a) (big_f a_1 a_2)) False % 5.13/5.38 Clause #7 (by clausification #[6]): ∀ (a a_1 a_2 a_3 : Iota), Eq ((big_f a a_1 → big_f (skS.0 0 a a_1 a_2 a_3) a) → big_f a a) True % 5.13/5.38 Clause #8 (by clausification #[6]): ∀ (a a_1 a_2 : Iota), Eq (And (big_f a a) (big_f a_1 a_2)) False % 5.13/5.38 Clause #9 (by clausification #[7]): ∀ (a a_1 a_2 a_3 : Iota), Or (Eq (big_f a a_1 → big_f (skS.0 0 a a_1 a_2 a_3) a) False) (Eq (big_f a a) True) % 5.13/5.38 Clause #10 (by clausification #[9]): ∀ (a a_1 : Iota), Or (Eq (big_f a a) True) (Eq (big_f a a_1) True) % 5.13/5.38 Clause #12 (by equality factoring #[10]): ∀ (a : Iota), Or (Ne True True) (Eq (big_f a a) True) % 5.13/5.38 Clause #13 (by clausification #[12]): ∀ (a : Iota), Or (Eq (big_f a a) True) (Or (Eq True False) (Eq True False)) % 5.13/5.38 Clause #15 (by clausification #[13]): ∀ (a : Iota), Or (Eq (big_f a a) True) (Eq True False) % 5.13/5.38 Clause #16 (by clausification #[15]): ∀ (a : Iota), Eq (big_f a a) True % 5.13/5.38 Clause #17 (by clausification #[8]): ∀ (a a_1 a_2 : Iota), Or (Eq (big_f a a) False) (Eq (big_f a_1 a_2) False) % 5.13/5.38 Clause #18 (by superposition #[17, 16]): ∀ (a a_1 : Iota), Or (Eq (big_f a a_1) False) (Eq False True) % 5.13/5.38 Clause #19 (by clausification #[18]): ∀ (a a_1 : Iota), Eq (big_f a a_1) False % 5.13/5.38 Clause #20 (by superposition #[19, 16]): Eq False True % 5.13/5.38 Clause #21 (by clausification #[20]): False % 5.13/5.38 SZS output end Proof for theBenchmark.p %------------------------------------------------------------------------------