%------------------------------------------------------------------------------ % File : Crossbow---0.1 % Problem : SYN348+1 : TPTP v8.1.0. Released v2.0.0. % Transfm : none % Format : tptp:raw % Command : do_Crossbow---0.1 %s % Computer : n004.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 600s % DateTime : Thu Jul 21 03:01:34 EDT 2022 % Result : CounterSatisfiable 0.20s 0.50s % Output : FiniteModel 0.20s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.07/0.12 % Problem : SYN348+1 : TPTP v8.1.0. Released v2.0.0. % 0.07/0.13 % Command : do_Crossbow---0.1 %s % 0.13/0.34 % Computer : n004.cluster.edu % 0.13/0.34 % Model : x86_64 x86_64 % 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.13/0.34 % Memory : 8042.1875MB % 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64 % 0.13/0.34 % CPULimit : 300 % 0.13/0.34 % WCLimit : 600 % 0.13/0.34 % DateTime : Tue Jul 12 07:45:37 EDT 2022 % 0.13/0.34 % CPUTime : % 0.13/0.35 /export/starexec/sandbox/solver/bin % 0.13/0.35 crossbow.opt % 0.13/0.35 do_Crossbow---0.1 % 0.13/0.35 eprover % 0.13/0.35 runsolver % 0.13/0.35 starexec_run_Crossbow---0.1 % 0.20/0.50 % SZS status CounterSatisfiable for theBenchmark.p % 0.20/0.50 % SZS output start FiniteModel for theBenchmark.p % 0.20/0.50 % domain size: 2 % 0.20/0.50 fof(interp, fi_domain, ![X] : (X = 0 | X = 1)). % 0.20/0.50 fof(interp, fi_predicates, big_f(0, 0) & ~big_f(0, 1) & big_f(1, 0) & % 0.20/0.50 big_f(1, 1)). % 0.20/0.50 fof(interp, fi_functors, esk1_1(0) = 1 & esk1_1(1) = 0). % 0.20/0.50 fof(interp, fi_functors, esk2_2(0, 0) = 0 & esk2_2(0, 1) = 0 & esk2_2(1, 0) = 0 & % 0.20/0.50 esk2_2(1, 1) = 0). % 0.20/0.50 fof(interp, fi_functors, esk3_2(0, 0) = 0 & esk3_2(0, 1) = 0 & esk3_2(1, 0) = 1 & % 0.20/0.50 esk3_2(1, 1) = 0). % 0.20/0.50 % SZS output end FiniteModel for theBenchmark.p % 0.20/0.50 % 0 lemma(s) from E % 0.20/0.50 % 129 pred(s) % 0.20/0.50 % 3 func(s) % 0.20/0.50 % 1 sort(s) % 0.20/0.50 % 192 clause(s) % 0.20/0.50 % Instantiating 1 (113 ms) % 0.20/0.50 % Solving (114 ms) % 0.20/0.50 % Instantiating 2 (114 ms) % 0.20/0.50 % Solving (118 ms) % 0.20/0.50 % % 0.20/0.50 % 1 model found (119 ms) %------------------------------------------------------------------------------