↑ Up

Duper---1.0.THM-Prf.s

View TPTP
Problem
Process solution in
SystemOnTSTP
Download .tgz
%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : SYN356^5 : TPTP v9.2.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n006.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Oct  3 08:07:29 PM UTC 2025

% Result   : Theorem 3.63s 3.83s
% Output   : Proof 3.63s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.11/0.13  % Problem    : SYN356^5 : TPTP v9.2.0. Released v4.0.0.
% 0.11/0.15  % Command    : duper %s
% 0.14/0.36  % Computer : n006.cluster.edu
% 0.14/0.36  % Model    : x86_64 x86_64
% 0.14/0.36  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.36  % Memory   : 8042.1875MB
% 0.14/0.36  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.36  % CPULimit   : 300
% 0.14/0.36  % WCLimit    : 300
% 0.14/0.36  % DateTime   : Thu Oct  2 15:21:38 EDT 2025
% 0.14/0.36  % CPUTime    : 
% 3.63/3.83  SZS status Theorem for theBenchmark.p
% 3.63/3.83  SZS output start Proof for theBenchmark.p
% 3.63/3.83  Clause #0 (by assumption #[]): Eq
% 3.63/3.83    (Not
% 3.63/3.83      (And (And (cR cA cB) (∀ (X Y : Iota), cR X Y → And (cR Y X) (cQ X Y))) (∀ (U V : Iota), cQ U V → cQ U U) →
% 3.63/3.83        And (cQ cA cA) (cQ cB cB)))
% 3.63/3.83    True
% 3.63/3.83  Clause #1 (by clausification #[0]): Eq
% 3.63/3.83    (And (And (cR cA cB) (∀ (X Y : Iota), cR X Y → And (cR Y X) (cQ X Y))) (∀ (U V : Iota), cQ U V → cQ U U) →
% 3.63/3.83      And (cQ cA cA) (cQ cB cB))
% 3.63/3.83    False
% 3.63/3.83  Clause #2 (by clausification #[1]): Eq (And (And (cR cA cB) (∀ (X Y : Iota), cR X Y → And (cR Y X) (cQ X Y))) (∀ (U V : Iota), cQ U V → cQ U U)) True
% 3.63/3.83  Clause #3 (by clausification #[1]): Eq (And (cQ cA cA) (cQ cB cB)) False
% 3.63/3.83  Clause #4 (by clausification #[2]): Eq (∀ (U V : Iota), cQ U V → cQ U U) True
% 3.63/3.83  Clause #5 (by clausification #[2]): Eq (And (cR cA cB) (∀ (X Y : Iota), cR X Y → And (cR Y X) (cQ X Y))) True
% 3.63/3.83  Clause #6 (by clausification #[4]): ∀ (a : Iota), Eq (∀ (V : Iota), cQ a V → cQ a a) True
% 3.63/3.83  Clause #7 (by clausification #[6]): ∀ (a a_1 : Iota), Eq (cQ a a_1 → cQ a a) True
% 3.63/3.83  Clause #8 (by clausification #[7]): ∀ (a a_1 : Iota), Or (Eq (cQ a a_1) False) (Eq (cQ a a) True)
% 3.63/3.83  Clause #9 (by clausification #[3]): Or (Eq (cQ cA cA) False) (Eq (cQ cB cB) False)
% 3.63/3.83  Clause #10 (by clausification #[5]): Eq (∀ (X Y : Iota), cR X Y → And (cR Y X) (cQ X Y)) True
% 3.63/3.83  Clause #11 (by clausification #[5]): Eq (cR cA cB) True
% 3.63/3.83  Clause #12 (by clausification #[10]): ∀ (a : Iota), Eq (∀ (Y : Iota), cR a Y → And (cR Y a) (cQ a Y)) True
% 3.63/3.83  Clause #13 (by clausification #[12]): ∀ (a a_1 : Iota), Eq (cR a a_1 → And (cR a_1 a) (cQ a a_1)) True
% 3.63/3.83  Clause #14 (by clausification #[13]): ∀ (a a_1 : Iota), Or (Eq (cR a a_1) False) (Eq (And (cR a_1 a) (cQ a a_1)) True)
% 3.63/3.83  Clause #15 (by clausification #[14]): ∀ (a a_1 : Iota), Or (Eq (cR a a_1) False) (Eq (cQ a a_1) True)
% 3.63/3.83  Clause #16 (by clausification #[14]): ∀ (a a_1 : Iota), Or (Eq (cR a a_1) False) (Eq (cR a_1 a) True)
% 3.63/3.83  Clause #17 (by superposition #[11, 15]): Or (Eq (cQ cA cB) True) (Eq False True)
% 3.63/3.83  Clause #18 (by clausification #[17]): Eq (cQ cA cB) True
% 3.63/3.83  Clause #19 (by superposition #[18, 8]): Or (Eq True False) (Eq (cQ cA cA) True)
% 3.63/3.83  Clause #20 (by superposition #[16, 11]): Or (Eq (cR cB cA) True) (Eq False True)
% 3.63/3.83  Clause #21 (by clausification #[20]): Eq (cR cB cA) True
% 3.63/3.83  Clause #22 (by superposition #[21, 15]): Or (Eq True False) (Eq (cQ cB cA) True)
% 3.63/3.83  Clause #24 (by clausification #[22]): Eq (cQ cB cA) True
% 3.63/3.83  Clause #25 (by superposition #[24, 8]): Or (Eq True False) (Eq (cQ cB cB) True)
% 3.63/3.83  Clause #26 (by clausification #[25]): Eq (cQ cB cB) True
% 3.63/3.83  Clause #27 (by clausification #[19]): Eq (cQ cA cA) True
% 3.63/3.83  Clause #28 (by backward demodulation #[27, 9]): Or (Eq True False) (Eq (cQ cB cB) False)
% 3.63/3.83  Clause #29 (by clausification #[28]): Eq (cQ cB cB) False
% 3.63/3.83  Clause #30 (by superposition #[29, 26]): Eq False True
% 3.63/3.83  Clause #31 (by clausification #[30]): False
% 3.63/3.83  SZS output end Proof for theBenchmark.p
%------------------------------------------------------------------------------