%------------------------------------------------------------------------------ % File : Duper---1.0 % Problem : SYN383+1 : TPTP v9.2.0. Released v2.0.0. % Transfm : none % Format : tptp:raw % Command : duper %s % Computer : n006.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 300s % DateTime : Fri Oct 3 08:07:33 PM UTC 2025 % Result : Theorem 3.62s 3.81s % Output : Proof 3.62s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.03/0.12 % Problem : SYN383+1 : TPTP v9.2.0. Released v2.0.0. % 0.03/0.13 % Command : duper %s % 0.13/0.34 % Computer : n006.cluster.edu % 0.13/0.34 % Model : x86_64 x86_64 % 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.13/0.34 % Memory : 8042.1875MB % 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64 % 0.13/0.34 % CPULimit : 300 % 0.13/0.34 % WCLimit : 300 % 0.13/0.34 % DateTime : Thu Oct 2 15:47:53 EDT 2025 % 0.13/0.34 % CPUTime : % 3.62/3.81 SZS status Theorem for theBenchmark.p % 3.62/3.81 SZS output start Proof for theBenchmark.p % 3.62/3.81 Clause #0 (by assumption #[]): Eq (Not (Exists fun X => ∀ (Y : Iota), And (big_p X) (big_q Y) → Or (big_q X) (big_p Y))) True % 3.62/3.81 Clause #1 (by clausification #[0]): Eq (Exists fun X => ∀ (Y : Iota), And (big_p X) (big_q Y) → Or (big_q X) (big_p Y)) False % 3.62/3.81 Clause #2 (by clausification #[1]): ∀ (a : Iota), Eq (∀ (Y : Iota), And (big_p a) (big_q Y) → Or (big_q a) (big_p Y)) False % 3.62/3.81 Clause #3 (by clausification #[2]): ∀ (a a_1 : Iota), Eq (Not (And (big_p a) (big_q (skS.0 0 a a_1)) → Or (big_q a) (big_p (skS.0 0 a a_1)))) True % 3.62/3.81 Clause #4 (by clausification #[3]): ∀ (a a_1 : Iota), Eq (And (big_p a) (big_q (skS.0 0 a a_1)) → Or (big_q a) (big_p (skS.0 0 a a_1))) False % 3.62/3.81 Clause #5 (by clausification #[4]): ∀ (a a_1 : Iota), Eq (And (big_p a) (big_q (skS.0 0 a a_1))) True % 3.62/3.81 Clause #6 (by clausification #[4]): ∀ (a a_1 : Iota), Eq (Or (big_q a) (big_p (skS.0 0 a a_1))) False % 3.62/3.81 Clause #8 (by clausification #[5]): ∀ (a : Iota), Eq (big_p a) True % 3.62/3.81 Clause #9 (by clausification #[6]): ∀ (a a_1 : Iota), Eq (big_p (skS.0 0 a a_1)) False % 3.62/3.81 Clause #11 (by superposition #[9, 8]): Eq False True % 3.62/3.81 Clause #12 (by clausification #[11]): False % 3.62/3.81 SZS output end Proof for theBenchmark.p %------------------------------------------------------------------------------