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SPASS---3.9.THM-Ref.s

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%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : SYN392+1 : TPTP v8.1.0. Released v2.0.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n016.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Thu Jul 21 12:21:02 EDT 2022

% Result   : Theorem 0.18s 0.44s
% Output   : Refutation 0.18s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    7
%            Number of leaves      :    8
% Syntax   : Number of clauses     :   15 (   4 unt;   7 nHn;  15 RR)
%            Number of literals    :   34 (   0 equ;  12 neg)
%            Maximal clause size   :    3 (   2 avg)
%            Maximal term depth    :    0 (   0 avg)
%            Number of predicates  :    4 (   3 usr;   4 prp; 0-0 aty)
%            Number of functors    :    0 (   0 usr;   0 con; --- aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    ( p1
    | p2
    | skC0 ),
    file('SYN392+1.p',unknown),
    [] ).

cnf(2,axiom,
    ( ~ p1
    | p2
    | skC0 ),
    file('SYN392+1.p',unknown),
    [] ).

cnf(3,axiom,
    ( ~ p2
    | p1
    | skC0 ),
    file('SYN392+1.p',unknown),
    [] ).

cnf(4,axiom,
    ( ~ skC0
    | p2
    | p1 ),
    file('SYN392+1.p',unknown),
    [] ).

cnf(5,axiom,
    ( ~ p1
    | ~ skC0
    | p2 ),
    file('SYN392+1.p',unknown),
    [] ).

cnf(6,axiom,
    ( ~ p2
    | ~ skC0
    | p1 ),
    file('SYN392+1.p',unknown),
    [] ).

cnf(7,axiom,
    ( ~ p1
    | ~ p2
    | skC0 ),
    file('SYN392+1.p',unknown),
    [] ).

cnf(8,axiom,
    ( ~ p1
    | ~ p2
    | ~ skC0 ),
    file('SYN392+1.p',unknown),
    [] ).

cnf(9,plain,
    ( p2
    | p1 ),
    inference(mrr,[status(thm)],[4,1]),
    [iquote('0:MRR:4.0,1.2')] ).

cnf(10,plain,
    ( p1
    | skC0 ),
    inference(mrr,[status(thm)],[3,9]),
    [iquote('0:MRR:3.0,9.0')] ).

cnf(11,plain,
    ( p2
    | skC0 ),
    inference(mrr,[status(thm)],[2,10]),
    [iquote('0:MRR:2.0,10.0')] ).

cnf(12,plain,
    skC0,
    inference(mrr,[status(thm)],[7,10,11]),
    [iquote('0:MRR:7.0,7.1,10.0,11.0')] ).

cnf(13,plain,
    p1,
    inference(mrr,[status(thm)],[6,9,12]),
    [iquote('0:MRR:6.0,6.1,9.0,12.0')] ).

cnf(14,plain,
    p2,
    inference(mrr,[status(thm)],[5,13,12]),
    [iquote('0:MRR:5.0,5.1,13.0,12.0')] ).

cnf(15,plain,
    $false,
    inference(mrr,[status(thm)],[8,13,14,12]),
    [iquote('0:MRR:8.0,8.1,8.2,13.0,14.0,12.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.11/0.12  % Problem  : SYN392+1 : TPTP v8.1.0. Released v2.0.0.
% 0.11/0.12  % Command  : run_spass %d %s
% 0.12/0.33  % Computer : n016.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 600
% 0.12/0.33  % DateTime : Mon Jul 11 17:21:28 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 0.18/0.44  
% 0.18/0.44  SPASS V 3.9 
% 0.18/0.44  SPASS beiseite: Proof found.
% 0.18/0.44  % SZS status Theorem
% 0.18/0.44  Problem: /export/starexec/sandbox2/benchmark/theBenchmark.p 
% 0.18/0.44  SPASS derived 0 clauses, backtracked 0 clauses, performed 0 splits and kept 8 clauses.
% 0.18/0.44  SPASS allocated 85056 KBytes.
% 0.18/0.44  SPASS spent	0:00:00.09 on the problem.
% 0.18/0.44  		0:00:00.04 for the input.
% 0.18/0.44  		0:00:00.03 for the FLOTTER CNF translation.
% 0.18/0.44  		0:00:00.00 for inferences.
% 0.18/0.44  		0:00:00.00 for the backtracking.
% 0.18/0.44  		0:00:00.00 for the reduction.
% 0.18/0.44  
% 0.18/0.44  
% 0.18/0.44  Here is a proof with depth 0, length 15 :
% 0.18/0.44  % SZS output start Refutation
% See solution above
% 0.18/0.44  Formulae used in the proof : pel14
% 0.18/0.44  
%------------------------------------------------------------------------------