↑ Up

Duper---1.0.THM-Prf.s

View TPTP
Problem
Process solution in
SystemOnTSTP
Download .tgz
%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : SYN398+1 : TPTP v9.2.0. Released v2.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n022.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Oct  3 08:07:35 PM UTC 2025

% Result   : Theorem 5.62s 5.85s
% Output   : Proof 5.62s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.02/0.10  % Problem    : SYN398+1 : TPTP v9.2.0. Released v2.0.0.
% 0.02/0.11  % Command    : duper %s
% 0.10/0.31  % Computer : n022.cluster.edu
% 0.10/0.31  % Model    : x86_64 x86_64
% 0.10/0.31  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.10/0.31  % Memory   : 8042.1875MB
% 0.10/0.31  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.10/0.31  % CPULimit   : 300
% 0.10/0.31  % WCLimit    : 300
% 0.10/0.31  % DateTime   : Thu Oct  2 15:40:23 EDT 2025
% 0.10/0.31  % CPUTime    : 
% 5.62/5.85  SZS status Theorem for theBenchmark.p
% 5.62/5.85  SZS output start Proof for theBenchmark.p
% 5.62/5.85  Clause #0 (by assumption #[]): Eq (Not (Iff (∀ (X : Iota), And p (f X)) (And p (∀ (Y : Iota), f Y)))) True
% 5.62/5.85  Clause #1 (by clausification #[0]): Eq (Iff (∀ (X : Iota), And p (f X)) (And p (∀ (Y : Iota), f Y))) False
% 5.62/5.85  Clause #2 (by clausification #[1]): Or (Eq (∀ (X : Iota), And p (f X)) False) (Eq (And p (∀ (Y : Iota), f Y)) False)
% 5.62/5.85  Clause #3 (by clausification #[1]): Or (Eq (∀ (X : Iota), And p (f X)) True) (Eq (And p (∀ (Y : Iota), f Y)) True)
% 5.62/5.85  Clause #4 (by clausification #[2]): ∀ (a : Iota), Or (Eq (And p (∀ (Y : Iota), f Y)) False) (Eq (Not (And p (f (skS.0 0 a)))) True)
% 5.62/5.85  Clause #5 (by clausification #[4]): ∀ (a : Iota), Or (Eq (Not (And p (f (skS.0 0 a)))) True) (Or (Eq p False) (Eq (∀ (Y : Iota), f Y) False))
% 5.62/5.85  Clause #6 (by clausification #[5]): ∀ (a : Iota), Or (Eq p False) (Or (Eq (∀ (Y : Iota), f Y) False) (Eq (And p (f (skS.0 0 a))) False))
% 5.62/5.85  Clause #7 (by clausification #[6]): ∀ (a a_1 : Iota), Or (Eq p False) (Or (Eq (And p (f (skS.0 0 a))) False) (Eq (Not (f (skS.0 1 a_1))) True))
% 5.62/5.85  Clause #8 (by clausification #[7]): ∀ (a a_1 : Iota), Or (Eq p False) (Or (Eq (Not (f (skS.0 1 a))) True) (Or (Eq p False) (Eq (f (skS.0 0 a_1)) False)))
% 5.62/5.85  Clause #9 (by clausification #[8]): ∀ (a a_1 : Iota), Or (Eq p False) (Or (Eq p False) (Or (Eq (f (skS.0 0 a)) False) (Eq (f (skS.0 1 a_1)) False)))
% 5.62/5.85  Clause #10 (by eliminate duplicate literals #[9]): ∀ (a a_1 : Iota), Or (Eq p False) (Or (Eq (f (skS.0 0 a)) False) (Eq (f (skS.0 1 a_1)) False))
% 5.62/5.85  Clause #11 (by clausification #[3]): ∀ (a : Iota), Or (Eq (And p (∀ (Y : Iota), f Y)) True) (Eq (And p (f a)) True)
% 5.62/5.85  Clause #12 (by clausification #[11]): ∀ (a : Iota), Or (Eq (And p (f a)) True) (Eq (∀ (Y : Iota), f Y) True)
% 5.62/5.85  Clause #13 (by clausification #[11]): ∀ (a : Iota), Or (Eq (And p (f a)) True) (Eq p True)
% 5.62/5.85  Clause #14 (by clausification #[12]): ∀ (a : Iota), Or (Eq (∀ (Y : Iota), f Y) True) (Eq (f a) True)
% 5.62/5.85  Clause #16 (by clausification #[14]): ∀ (a a_1 : Iota), Or (Eq (f a) True) (Eq (f a_1) True)
% 5.62/5.85  Clause #17 (by equality factoring #[16]): ∀ (a : Iota), Or (Ne True True) (Eq (f a) True)
% 5.62/5.85  Clause #18 (by clausification #[17]): ∀ (a : Iota), Or (Eq (f a) True) (Or (Eq True False) (Eq True False))
% 5.62/5.85  Clause #20 (by clausification #[18]): ∀ (a : Iota), Or (Eq (f a) True) (Eq True False)
% 5.62/5.85  Clause #21 (by clausification #[20]): ∀ (a : Iota), Eq (f a) True
% 5.62/5.85  Clause #23 (by clausification #[13]): Or (Eq p True) (Eq p True)
% 5.62/5.85  Clause #24 (by eliminate duplicate literals #[23]): Eq p True
% 5.62/5.85  Clause #25 (by backward demodulation #[24, 10]): ∀ (a a_1 : Iota), Or (Eq True False) (Or (Eq (f (skS.0 0 a)) False) (Eq (f (skS.0 1 a_1)) False))
% 5.62/5.85  Clause #26 (by clausification #[25]): ∀ (a a_1 : Iota), Or (Eq (f (skS.0 0 a)) False) (Eq (f (skS.0 1 a_1)) False)
% 5.62/5.85  Clause #27 (by superposition #[26, 21]): ∀ (a : Iota), Or (Eq (f (skS.0 1 a)) False) (Eq False True)
% 5.62/5.85  Clause #28 (by clausification #[27]): ∀ (a : Iota), Eq (f (skS.0 1 a)) False
% 5.62/5.85  Clause #29 (by superposition #[28, 21]): Eq False True
% 5.62/5.85  Clause #30 (by clausification #[29]): False
% 5.62/5.85  SZS output end Proof for theBenchmark.p
%------------------------------------------------------------------------------