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Prover9---2026-6A.THM-CRf.s

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%------------------------------------------------------------------------------
% File     : Prover9---2026-6A
% Problem  : SYN398+1 : TPTP v9.3.1. Released v2.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : prover9 -casc 300 -f /export/starexec/sandbox/benchmark/theBenchmark.p

% Computer : n020.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8046.5625MB
% OS       : Linux 6.8.0-71-generic
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Sun Sep 27 09:37:48 AM UTC 2026

% Result   : Theorem 0.09s 0.38s
% Output   : CNFRefutation 0.09s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    8
%            Number of leaves      :    1
% Syntax   : Number of formulae    :   12 (   4 unt;   0 def)
%            Number of atoms       :   41 (   0 equ)
%            Maximal formula atoms :    8 (   3 avg)
%            Number of connectives :   47 (  18   ~;  15   |;  12   &)
%                                         (   2 <=>;   0  =>;   0  <=;   0 <~>)
%            Maximal formula depth :    6 (   3 avg)
%            Maximal term depth    :    1 (   1 avg)
%            Number of predicates  :    3 (   2 usr;   2 prp; 0-1 aty)
%            Number of functors    :    2 (   2 usr;   2 con; 0-0 aty)
%            Number of variables   :   15 (   3 sgn  10   !;   2   ?)

% Comments : 
%------------------------------------------------------------------------------
fof(kalish215,conjecture,
    ( ! [X] :
        ( f(X)
        & p )
  <=> ( ! [Y] : f(Y)
      & p ) ),
    file('theBenchmark.p',kalish215) ).

fof(kalish215_neg,negated_conjecture,
    ~ ( ! [X] :
          ( f(X)
          & p )
    <=> ( ! [Y] : f(Y)
        & p ) ),
    inference(assume_negation,[status(cth)],[kalish215]) ).

fof(nnf_1,plain,
    ( ( ? [Y] : ~ f(Y)
      | ~ p
      | ? [X] :
          ( ~ f(X)
          | ~ p ) )
    & ( ( ! [X1] : f(X1)
        & p )
      | ! [X0] :
          ( f(X0)
          & p ) ) ),
    inference(fof_nnf,[status(thm)],[kalish215_neg]) ).

fof(sk_kalish215_neg_sk,plain,
    ( ( ~ f(sK1)
      | ~ p
      | ~ f(sK0)
      | ~ p )
    & ( ( ! [X1] : f(X1)
        & p )
      | ! [X0] :
          ( f(X0)
          & p ) ) ),
    inference(skolemize,[status(esa),new_symbols(skolem,[sK0,sK1]),skolemize(X,sK0),skolemize(Y,sK1)],[nnf_1]) ).

fof(sk_kalish215_neg,plain,
    ( ( ~ f(sK1)
      | ~ f(sK0)
      | ~ p )
    & ! [VAR_0,VAR_1] :
        ( f(VAR_1)
        | f(VAR_0) )
    & p ),
    inference(cnf_transformation,[status(thm)],[sk_kalish215_neg_sk]) ).

cnf(c_2,negated_conjecture,
    p,
    inference(split_conjunct,[status(thm)],[sk_kalish215_neg]) ).

cnf(c_3,negated_conjecture,
    ( f(B)
    | f(A) ),
    inference(split_conjunct,[status(thm)],[sk_kalish215_neg]) ).

cnf(c_4,negated_conjecture,
    ( ~ f(sK1)
    | ~ f(sK0)
    | ~ p ),
    inference(split_conjunct,[status(thm)],[sk_kalish215_neg]) ).

cnf(c_5,negated_conjecture,
    ( ~ f(sK1)
    | ~ f(sK0) ),
    inference(resolve,[status(thm)],[c_2,c_4]) ).

cnf(c_6,plain,
    f(A),
    inference(factor,[status(thm)],[c_3]) ).

cnf(c_8,negated_conjecture,
    ~ f(sK1),
    inference(resolve,[status(thm)],[c_6,c_5]) ).

cnf(c_7,negated_conjecture,
    $false,
    inference(resolve,[status(thm)],[c_6,c_8]) ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.03  % Problem  : SYN398+1 : TPTP v9.3.1. Released v2.0.0.
% 0.00/0.04  % Command  : prover9 -casc 300 -f /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.09/0.36  % Computer : n020.cluster.edu
% 0.09/0.36  % Model    : x86_64 x86_64
% 0.09/0.36  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.09/0.36  % Memory   : 8046.5625MB
% 0.09/0.36  % OS       : Linux 6.8.0-71-generic
% 0.09/0.36  % CPULimit : 300
% 0.09/0.36  % WCLimit  : 300
% 0.09/0.36  % DateTime : Sat Sep 26 17:41:34 UTC 2026
% 0.09/0.36  % CPUTime  : 
% 0.09/0.37  % Prover9 (64) version 2026-6A, July 2026, CASC-J13.
% 0.09/0.37  % Process 2145580 was started by sandbox on n020,
% 0.09/0.37  % Sat Sep 26 17:41:34 2026
% 0.09/0.37  % The command was "/export/starexec/sandbox/solver/bin/prover9 -casc 300 -f /export/starexec/sandbox/benchmark/theBenchmark.p".
% 0.09/0.37  
% 0.09/0.37  % From the command line: assign(max_seconds, 300).
% 0.09/0.38  
% 0.09/0.38  % SZS status Theorem for theBenchmark
% 0.09/0.38  
% 0.09/0.38  % Proof 1 at 0.00 (+ 0.00) seconds.
% 0.09/0.38  % Length of proof is 7.
% 0.09/0.38  % Level of proof is 3.
% 0.09/0.38  % Maximum clause weight is 4.000.
% 0.09/0.38  % Given clauses 0.
% 0.09/0.38  
% 0.09/0.38  % SZS output start CNFRefutation for theBenchmark
% See solution above
%------------------------------------------------------------------------------