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Duper---1.0.THM-Prf.s

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%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : SYN399+1 : TPTP v9.2.0. Released v2.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n031.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Oct  3 08:07:36 PM UTC 2025

% Result   : Theorem 4.70s 4.91s
% Output   : Proof 4.70s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.12/0.12  % Problem    : SYN399+1 : TPTP v9.2.0. Released v2.0.0.
% 0.12/0.13  % Command    : duper %s
% 0.13/0.34  % Computer : n031.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit   : 300
% 0.13/0.34  % WCLimit    : 300
% 0.13/0.34  % DateTime   : Thu Oct  2 15:40:38 EDT 2025
% 0.13/0.34  % CPUTime    : 
% 4.70/4.91  SZS status Theorem for theBenchmark.p
% 4.70/4.91  SZS output start Proof for theBenchmark.p
% 4.70/4.91  Clause #0 (by assumption #[]): Eq (Not ((∀ (X : Iota), Iff (f X) p) → Iff (∀ (Y : Iota), f Y) p)) True
% 4.70/4.91  Clause #1 (by clausification #[0]): Eq ((∀ (X : Iota), Iff (f X) p) → Iff (∀ (Y : Iota), f Y) p) False
% 4.70/4.91  Clause #2 (by clausification #[1]): Eq (∀ (X : Iota), Iff (f X) p) True
% 4.70/4.91  Clause #3 (by clausification #[1]): Eq (Iff (∀ (Y : Iota), f Y) p) False
% 4.70/4.91  Clause #4 (by clausification #[2]): ∀ (a : Iota), Eq (Iff (f a) p) True
% 4.70/4.91  Clause #5 (by clausification #[4]): ∀ (a : Iota), Or (Eq (f a) True) (Eq p False)
% 4.70/4.91  Clause #6 (by clausification #[4]): ∀ (a : Iota), Or (Eq (f a) False) (Eq p True)
% 4.70/4.91  Clause #7 (by clausification #[3]): Or (Eq (∀ (Y : Iota), f Y) False) (Eq p False)
% 4.70/4.91  Clause #8 (by clausification #[3]): Or (Eq (∀ (Y : Iota), f Y) True) (Eq p True)
% 4.70/4.91  Clause #9 (by clausification #[7]): ∀ (a : Iota), Or (Eq p False) (Eq (Not (f (skS.0 0 a))) True)
% 4.70/4.91  Clause #10 (by clausification #[9]): ∀ (a : Iota), Or (Eq p False) (Eq (f (skS.0 0 a)) False)
% 4.70/4.91  Clause #11 (by clausification #[8]): ∀ (a : Iota), Or (Eq p True) (Eq (f a) True)
% 4.70/4.91  Clause #12 (by superposition #[11, 6]): Or (Eq p True) (Or (Eq True False) (Eq p True))
% 4.70/4.91  Clause #13 (by clausification #[12]): Or (Eq p True) (Eq p True)
% 4.70/4.91  Clause #14 (by eliminate duplicate literals #[13]): Eq p True
% 4.70/4.91  Clause #15 (by backward demodulation #[14, 5]): ∀ (a : Iota), Or (Eq (f a) True) (Eq True False)
% 4.70/4.91  Clause #17 (by backward demodulation #[14, 10]): ∀ (a : Iota), Or (Eq True False) (Eq (f (skS.0 0 a)) False)
% 4.70/4.91  Clause #19 (by clausification #[15]): ∀ (a : Iota), Eq (f a) True
% 4.70/4.91  Clause #20 (by clausification #[17]): ∀ (a : Iota), Eq (f (skS.0 0 a)) False
% 4.70/4.91  Clause #21 (by superposition #[20, 19]): Eq False True
% 4.70/4.91  Clause #22 (by clausification #[21]): False
% 4.70/4.91  SZS output end Proof for theBenchmark.p
%------------------------------------------------------------------------------