%------------------------------------------------------------------------------ % File : Duper---1.0 % Problem : SYN403+1 : TPTP v9.2.0. Released v2.0.0. % Transfm : none % Format : tptp:raw % Command : duper %s % Computer : n010.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 300s % DateTime : Fri Oct 3 08:07:36 PM UTC 2025 % Result : Theorem 4.75s 5.00s % Output : Proof 4.75s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.10/0.14 % Problem : SYN403+1 : TPTP v9.2.0. Released v2.0.0. % 0.10/0.15 % Command : duper %s % 0.14/0.37 % Computer : n010.cluster.edu % 0.14/0.37 % Model : x86_64 x86_64 % 0.14/0.37 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.14/0.37 % Memory : 8042.1875MB % 0.14/0.37 % OS : Linux 3.10.0-693.el7.x86_64 % 0.14/0.37 % CPULimit : 300 % 0.14/0.37 % WCLimit : 300 % 0.14/0.38 % DateTime : Thu Oct 2 15:05:08 EDT 2025 % 0.14/0.38 % CPUTime : % 4.75/5.00 SZS status Theorem for theBenchmark.p % 4.75/5.00 SZS output start Proof for theBenchmark.p % 4.75/5.00 Clause #0 (by assumption #[]): Eq (Not (∀ (X : Iota), And (f X → g X) (g X → h X) → f X → h X)) True % 4.75/5.00 Clause #1 (by clausification #[0]): Eq (∀ (X : Iota), And (f X → g X) (g X → h X) → f X → h X) False % 4.75/5.00 Clause #2 (by clausification #[1]): ∀ (a : Iota), % 4.75/5.00 Eq (Not (And (f (skS.0 0 a) → g (skS.0 0 a)) (g (skS.0 0 a) → h (skS.0 0 a)) → f (skS.0 0 a) → h (skS.0 0 a))) True % 4.75/5.00 Clause #3 (by clausification #[2]): ∀ (a : Iota), % 4.75/5.00 Eq (And (f (skS.0 0 a) → g (skS.0 0 a)) (g (skS.0 0 a) → h (skS.0 0 a)) → f (skS.0 0 a) → h (skS.0 0 a)) False % 4.75/5.00 Clause #4 (by clausification #[3]): ∀ (a : Iota), Eq (And (f (skS.0 0 a) → g (skS.0 0 a)) (g (skS.0 0 a) → h (skS.0 0 a))) True % 4.75/5.00 Clause #5 (by clausification #[3]): ∀ (a : Iota), Eq (f (skS.0 0 a) → h (skS.0 0 a)) False % 4.75/5.00 Clause #6 (by clausification #[4]): ∀ (a : Iota), Eq (g (skS.0 0 a) → h (skS.0 0 a)) True % 4.75/5.00 Clause #7 (by clausification #[4]): ∀ (a : Iota), Eq (f (skS.0 0 a) → g (skS.0 0 a)) True % 4.75/5.00 Clause #8 (by clausification #[6]): ∀ (a : Iota), Or (Eq (g (skS.0 0 a)) False) (Eq (h (skS.0 0 a)) True) % 4.75/5.00 Clause #9 (by clausification #[5]): ∀ (a : Iota), Eq (f (skS.0 0 a)) True % 4.75/5.00 Clause #10 (by clausification #[5]): ∀ (a : Iota), Eq (h (skS.0 0 a)) False % 4.75/5.00 Clause #11 (by backward demodulation #[10, 8]): ∀ (a : Iota), Or (Eq (g (skS.0 0 a)) False) (Eq False True) % 4.75/5.00 Clause #12 (by clausification #[7]): ∀ (a : Iota), Or (Eq (f (skS.0 0 a)) False) (Eq (g (skS.0 0 a)) True) % 4.75/5.00 Clause #13 (by forward demodulation #[12, 9]): ∀ (a : Iota), Or (Eq True False) (Eq (g (skS.0 0 a)) True) % 4.75/5.00 Clause #14 (by clausification #[13]): ∀ (a : Iota), Eq (g (skS.0 0 a)) True % 4.75/5.00 Clause #15 (by clausification #[11]): ∀ (a : Iota), Eq (g (skS.0 0 a)) False % 4.75/5.00 Clause #16 (by superposition #[15, 14]): Eq False True % 4.75/5.00 Clause #17 (by clausification #[16]): False % 4.75/5.00 SZS output end Proof for theBenchmark.p %------------------------------------------------------------------------------