%------------------------------------------------------------------------------ % File : Duper---1.0 % Problem : SYN408+1 : TPTP v9.2.0. Released v2.0.0. % Transfm : none % Format : tptp:raw % Command : duper %s % Computer : n023.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 300s % DateTime : Fri Oct 3 08:07:37 PM UTC 2025 % Result : Theorem 5.39s 5.62s % Output : Proof 5.39s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.05/0.11 % Problem : SYN408+1 : TPTP v9.2.0. Released v2.0.0. % 0.05/0.12 % Command : duper %s % 0.10/0.33 % Computer : n023.cluster.edu % 0.10/0.33 % Model : x86_64 x86_64 % 0.10/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.10/0.33 % Memory : 8042.1875MB % 0.10/0.33 % OS : Linux 3.10.0-693.el7.x86_64 % 0.10/0.33 % CPULimit : 300 % 0.10/0.33 % WCLimit : 300 % 0.10/0.33 % DateTime : Thu Oct 2 15:43:08 EDT 2025 % 0.10/0.33 % CPUTime : % 5.39/5.62 SZS status Theorem for theBenchmark.p % 5.39/5.62 SZS output start Proof for theBenchmark.p % 5.39/5.62 Clause #0 (by assumption #[]): Eq (Not (Not (Exists fun X => f X) → ∀ (Y : Iota), f Y → g Y)) True % 5.39/5.62 Clause #1 (by betaEtaReduce #[0]): Eq (Not (Not (Exists f) → ∀ (Y : Iota), f Y → g Y)) True % 5.39/5.62 Clause #2 (by clausification #[1]): Eq (Not (Exists f) → ∀ (Y : Iota), f Y → g Y) False % 5.39/5.62 Clause #3 (by clausification #[2]): Eq (Not (Exists f)) True % 5.39/5.62 Clause #4 (by clausification #[2]): Eq (∀ (Y : Iota), f Y → g Y) False % 5.39/5.62 Clause #5 (by clausification #[3]): Eq (Exists f) False % 5.39/5.62 Clause #6 (by clausification #[5]): ∀ (a : Iota), Eq (f a) False % 5.39/5.62 Clause #7 (by clausification #[4]): ∀ (a : Iota), Eq (Not (f (skS.0 0 a) → g (skS.0 0 a))) True % 5.39/5.62 Clause #8 (by clausification #[7]): ∀ (a : Iota), Eq (f (skS.0 0 a) → g (skS.0 0 a)) False % 5.39/5.62 Clause #9 (by clausification #[8]): ∀ (a : Iota), Eq (f (skS.0 0 a)) True % 5.39/5.62 Clause #11 (by superposition #[9, 6]): Eq True False % 5.39/5.62 Clause #12 (by clausification #[11]): False % 5.39/5.62 SZS output end Proof for theBenchmark.p %------------------------------------------------------------------------------