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Duper---1.0.THM-Prf.s

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%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : SYN412+1 : TPTP v9.2.0. Released v2.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n011.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Oct  3 08:07:37 PM UTC 2025

% Result   : Theorem 3.46s 3.61s
% Output   : Proof 3.46s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.11  % Problem    : SYN412+1 : TPTP v9.2.0. Released v2.0.0.
% 0.03/0.12  % Command    : duper %s
% 0.13/0.33  % Computer : n011.cluster.edu
% 0.13/0.33  % Model    : x86_64 x86_64
% 0.13/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.33  % Memory   : 8042.1875MB
% 0.13/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.33  % CPULimit   : 300
% 0.13/0.33  % WCLimit    : 300
% 0.13/0.33  % DateTime   : Thu Oct  2 15:35:38 EDT 2025
% 0.13/0.33  % CPUTime    : 
% 3.46/3.61  SZS status Theorem for theBenchmark.p
% 3.46/3.61  SZS output start Proof for theBenchmark.p
% 3.46/3.61  Clause #0 (by assumption #[]): Eq (Not (Not (Exists fun X => ∀ (Y : Iota), Iff (f X Y) (Not (f X X))))) True
% 3.46/3.61  Clause #1 (by clausification #[0]): Eq (Not (Exists fun X => ∀ (Y : Iota), Iff (f X Y) (Not (f X X)))) False
% 3.46/3.61  Clause #2 (by clausification #[1]): Eq (Exists fun X => ∀ (Y : Iota), Iff (f X Y) (Not (f X X))) True
% 3.46/3.61  Clause #3 (by clausification #[2]): ∀ (a : Iota), Eq (∀ (Y : Iota), Iff (f (skS.0 0 a) Y) (Not (f (skS.0 0 a) (skS.0 0 a)))) True
% 3.46/3.61  Clause #4 (by clausification #[3]): ∀ (a a_1 : Iota), Eq (Iff (f (skS.0 0 a) a_1) (Not (f (skS.0 0 a) (skS.0 0 a)))) True
% 3.46/3.61  Clause #5 (by clausification #[4]): ∀ (a a_1 : Iota), Or (Eq (f (skS.0 0 a) a_1) True) (Eq (Not (f (skS.0 0 a) (skS.0 0 a))) False)
% 3.46/3.61  Clause #6 (by clausification #[4]): ∀ (a a_1 : Iota), Or (Eq (f (skS.0 0 a) a_1) False) (Eq (Not (f (skS.0 0 a) (skS.0 0 a))) True)
% 3.46/3.61  Clause #7 (by clausification #[5]): ∀ (a a_1 : Iota), Or (Eq (f (skS.0 0 a) a_1) True) (Eq (f (skS.0 0 a) (skS.0 0 a)) True)
% 3.46/3.61  Clause #8 (by equality factoring #[7]): ∀ (a : Iota), Or (Ne True True) (Eq (f (skS.0 0 a) (skS.0 0 a)) True)
% 3.46/3.61  Clause #9 (by clausification #[8]): ∀ (a : Iota), Or (Eq (f (skS.0 0 a) (skS.0 0 a)) True) (Or (Eq True False) (Eq True False))
% 3.46/3.61  Clause #11 (by clausification #[9]): ∀ (a : Iota), Or (Eq (f (skS.0 0 a) (skS.0 0 a)) True) (Eq True False)
% 3.46/3.61  Clause #12 (by clausification #[11]): ∀ (a : Iota), Eq (f (skS.0 0 a) (skS.0 0 a)) True
% 3.46/3.61  Clause #13 (by clausification #[6]): ∀ (a a_1 : Iota), Or (Eq (f (skS.0 0 a) a_1) False) (Eq (f (skS.0 0 a) (skS.0 0 a)) False)
% 3.46/3.61  Clause #14 (by superposition #[13, 12]): ∀ (a : Iota), Or (Eq (f (skS.0 0 a) (skS.0 0 a)) False) (Eq False True)
% 3.46/3.61  Clause #15 (by clausification #[14]): ∀ (a : Iota), Eq (f (skS.0 0 a) (skS.0 0 a)) False
% 3.46/3.61  Clause #16 (by superposition #[15, 12]): Eq False True
% 3.46/3.61  Clause #17 (by clausification #[16]): False
% 3.46/3.61  SZS output end Proof for theBenchmark.p
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