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Duper---1.0.THM-Prf.s

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%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : SYN932+1 : TPTP v9.2.0. Released v3.1.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n003.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Oct  3 08:08:16 PM UTC 2025

% Result   : Theorem 4.74s 4.89s
% Output   : Proof 4.74s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.11/0.12  % Problem    : SYN932+1 : TPTP v9.2.0. Released v3.1.0.
% 0.11/0.13  % Command    : duper %s
% 0.13/0.34  % Computer : n003.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit   : 300
% 0.13/0.34  % WCLimit    : 300
% 0.13/0.34  % DateTime   : Thu Oct  2 15:29:38 EDT 2025
% 0.13/0.34  % CPUTime    : 
% 4.74/4.89  SZS status Theorem for theBenchmark.p
% 4.74/4.89  SZS output start Proof for theBenchmark.p
% 4.74/4.89  Clause #0 (by assumption #[]): Eq (Not (Iff (Exists fun X => c) c)) True
% 4.74/4.89  Clause #1 (by clausification #[0]): Eq (Iff (Exists fun X => c) c) False
% 4.74/4.89  Clause #2 (by clausification #[1]): Or (Eq (Exists fun X => c) False) (Eq c False)
% 4.74/4.89  Clause #3 (by clausification #[1]): Or (Eq (Exists fun X => c) True) (Eq c True)
% 4.74/4.89  Clause #4 (by clausification #[2]): Iota → Or (Eq c False) (Eq c False)
% 4.74/4.89  Clause #5 (by eliminate duplicate literals #[4]): Eq c False
% 4.74/4.89  Clause #6 (by clausification #[3]): Iota → Or (Eq c True) (Eq c True)
% 4.74/4.89  Clause #7 (by eliminate duplicate literals #[6]): Eq c True
% 4.74/4.89  Clause #8 (by superposition #[7, 5]): Eq True False
% 4.74/4.89  Clause #9 (by clausification #[8]): False
% 4.74/4.89  SZS output end Proof for theBenchmark.p
%------------------------------------------------------------------------------