%------------------------------------------------------------------------------ % File : Duper---1.0 % Problem : SYN933+1 : TPTP v9.2.0. Released v3.1.0. % Transfm : none % Format : tptp:raw % Command : duper %s % Computer : n024.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 300s % DateTime : Fri Oct 3 08:08:16 PM UTC 2025 % Result : Theorem 4.14s 4.30s % Output : Proof 4.14s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.10/0.11 % Problem : SYN933+1 : TPTP v9.2.0. Released v3.1.0. % 0.10/0.13 % Command : duper %s % 0.13/0.34 % Computer : n024.cluster.edu % 0.13/0.34 % Model : x86_64 x86_64 % 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.13/0.34 % Memory : 8042.1875MB % 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64 % 0.13/0.34 % CPULimit : 300 % 0.13/0.34 % WCLimit : 300 % 0.13/0.34 % DateTime : Thu Oct 2 15:24:38 EDT 2025 % 0.13/0.34 % CPUTime : % 4.14/4.30 SZS status Theorem for theBenchmark.p % 4.14/4.30 SZS output start Proof for theBenchmark.p % 4.14/4.30 Clause #0 (by assumption #[]): Eq (Not (Iff (Iota → c) c)) True % 4.14/4.30 Clause #1 (by clausification #[0]): Eq (Iff (Iota → c) c) False % 4.14/4.30 Clause #2 (by clausification #[1]): Or (Eq (Iota → c) False) (Eq c False) % 4.14/4.30 Clause #3 (by clausification #[1]): Or (Eq (Iota → c) True) (Eq c True) % 4.14/4.30 Clause #4 (by clausification #[2]): Iota → Or (Eq c False) (Eq (Not c) True) % 4.14/4.30 Clause #5 (by clausification #[4]): Or (Eq c False) (Eq c False) % 4.14/4.30 Clause #6 (by eliminate duplicate literals #[5]): Eq c False % 4.14/4.30 Clause #7 (by clausification #[3]): Iota → Or (Eq c True) (Eq c True) % 4.14/4.30 Clause #8 (by eliminate duplicate literals #[7]): Eq c True % 4.14/4.30 Clause #9 (by superposition #[8, 6]): Eq True False % 4.14/4.30 Clause #10 (by clausification #[9]): False % 4.14/4.30 SZS output end Proof for theBenchmark.p %------------------------------------------------------------------------------