%------------------------------------------------------------------------------ % File : Duper---1.0 % Problem : SYN935+1 : TPTP v9.2.0. Released v3.1.0. % Transfm : none % Format : tptp:raw % Command : duper %s % Computer : n016.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 300s % DateTime : Fri Oct 3 08:08:16 PM UTC 2025 % Result : Theorem 3.52s 3.75s % Output : Proof 3.52s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.03/0.14 % Problem : SYN935+1 : TPTP v9.2.0. Released v3.1.0. % 0.03/0.15 % Command : duper %s % 0.16/0.37 % Computer : n016.cluster.edu % 0.16/0.37 % Model : x86_64 x86_64 % 0.16/0.37 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.16/0.37 % Memory : 8042.1875MB % 0.16/0.37 % OS : Linux 3.10.0-693.el7.x86_64 % 0.16/0.37 % CPULimit : 300 % 0.16/0.37 % WCLimit : 300 % 0.16/0.37 % DateTime : Thu Oct 2 15:03:38 EDT 2025 % 0.16/0.37 % CPUTime : % 3.52/3.75 SZS status Theorem for theBenchmark.p % 3.52/3.75 SZS output start Proof for theBenchmark.p % 3.52/3.75 Clause #0 (by assumption #[]): Eq (Not (Iff (Exists fun X => p X → c) ((∀ (X : Iota), p X) → c))) True % 3.52/3.75 Clause #1 (by clausification #[0]): Eq (Iff (Exists fun X => p X → c) ((∀ (X : Iota), p X) → c)) False % 3.52/3.75 Clause #2 (by clausification #[1]): Or (Eq (Exists fun X => p X → c) False) (Eq ((∀ (X : Iota), p X) → c) False) % 3.52/3.75 Clause #3 (by clausification #[1]): Or (Eq (Exists fun X => p X → c) True) (Eq ((∀ (X : Iota), p X) → c) True) % 3.52/3.75 Clause #4 (by clausification #[2]): ∀ (a : Iota), Or (Eq ((∀ (X : Iota), p X) → c) False) (Eq (p a → c) False) % 3.52/3.75 Clause #5 (by clausification #[4]): ∀ (a : Iota), Or (Eq (p a → c) False) (Eq (∀ (X : Iota), p X) True) % 3.52/3.75 Clause #6 (by clausification #[4]): ∀ (a : Iota), Or (Eq (p a → c) False) (Eq c False) % 3.52/3.75 Clause #7 (by clausification #[5]): ∀ (a : Iota), Or (Eq (∀ (X : Iota), p X) True) (Eq (p a) True) % 3.52/3.75 Clause #9 (by clausification #[7]): ∀ (a a_1 : Iota), Or (Eq (p a) True) (Eq (p a_1) True) % 3.52/3.75 Clause #10 (by equality factoring #[9]): ∀ (a : Iota), Or (Ne True True) (Eq (p a) True) % 3.52/3.75 Clause #11 (by clausification #[10]): ∀ (a : Iota), Or (Eq (p a) True) (Or (Eq True False) (Eq True False)) % 3.52/3.75 Clause #13 (by clausification #[11]): ∀ (a : Iota), Or (Eq (p a) True) (Eq True False) % 3.52/3.75 Clause #14 (by clausification #[13]): ∀ (a : Iota), Eq (p a) True % 3.52/3.75 Clause #16 (by clausification #[6]): Or (Eq c False) (Eq c False) % 3.52/3.75 Clause #17 (by eliminate duplicate literals #[16]): Eq c False % 3.52/3.75 Clause #18 (by clausification #[3]): ∀ (a : Iota), Or (Eq ((∀ (X : Iota), p X) → c) True) (Eq (p (skS.0 0 a) → c) True) % 3.52/3.75 Clause #19 (by clausification #[18]): ∀ (a : Iota), Or (Eq (p (skS.0 0 a) → c) True) (Or (Eq (∀ (X : Iota), p X) False) (Eq c True)) % 3.52/3.75 Clause #20 (by clausification #[19]): ∀ (a : Iota), Or (Eq (∀ (X : Iota), p X) False) (Or (Eq c True) (Or (Eq (p (skS.0 0 a)) False) (Eq c True))) % 3.52/3.75 Clause #21 (by clausification #[20]): ∀ (a a_1 : Iota), Or (Eq c True) (Or (Eq (p (skS.0 0 a)) False) (Or (Eq c True) (Eq (Not (p (skS.0 1 a_1))) True))) % 3.52/3.75 Clause #22 (by clausification #[21]): ∀ (a a_1 : Iota), Or (Eq c True) (Or (Eq (p (skS.0 0 a)) False) (Or (Eq c True) (Eq (p (skS.0 1 a_1)) False))) % 3.52/3.75 Clause #23 (by eliminate duplicate literals #[22]): ∀ (a a_1 : Iota), Or (Eq c True) (Or (Eq (p (skS.0 0 a)) False) (Eq (p (skS.0 1 a_1)) False)) % 3.52/3.75 Clause #24 (by forward demodulation #[23, 17]): ∀ (a a_1 : Iota), Or (Eq False True) (Or (Eq (p (skS.0 0 a)) False) (Eq (p (skS.0 1 a_1)) False)) % 3.52/3.75 Clause #25 (by clausification #[24]): ∀ (a a_1 : Iota), Or (Eq (p (skS.0 0 a)) False) (Eq (p (skS.0 1 a_1)) False) % 3.52/3.75 Clause #26 (by superposition #[25, 14]): ∀ (a : Iota), Or (Eq (p (skS.0 1 a)) False) (Eq False True) % 3.52/3.75 Clause #27 (by clausification #[26]): ∀ (a : Iota), Eq (p (skS.0 1 a)) False % 3.52/3.75 Clause #28 (by superposition #[27, 14]): Eq False True % 3.52/3.75 Clause #29 (by clausification #[28]): False % 3.52/3.75 SZS output end Proof for theBenchmark.p %------------------------------------------------------------------------------