%------------------------------------------------------------------------------ % File : Duper---1.0 % Problem : SYN948+1 : TPTP v9.2.0. Released v3.1.0. % Transfm : none % Format : tptp:raw % Command : duper %s % Computer : n024.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 300s % DateTime : Fri Oct 3 08:08:17 PM UTC 2025 % Result : Theorem 3.47s 3.67s % Output : Proof 3.47s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.02/0.12 % Problem : SYN948+1 : TPTP v9.2.0. Released v3.1.0. % 0.02/0.14 % Command : duper %s % 0.13/0.34 % Computer : n024.cluster.edu % 0.13/0.34 % Model : x86_64 x86_64 % 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.13/0.34 % Memory : 8042.1875MB % 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64 % 0.13/0.34 % CPULimit : 300 % 0.13/0.35 % WCLimit : 300 % 0.13/0.35 % DateTime : Thu Oct 2 15:12:53 EDT 2025 % 0.13/0.35 % CPUTime : % 3.47/3.67 SZS status Theorem for theBenchmark.p % 3.47/3.67 SZS output start Proof for theBenchmark.p % 3.47/3.67 Clause #0 (by assumption #[]): Eq (Not ((∀ (X : Iota), Exists fun Y => And (a X Y) (a Y Y)) → Exists fun Z => a Z Z)) True % 3.47/3.67 Clause #1 (by clausification #[0]): Eq ((∀ (X : Iota), Exists fun Y => And (a X Y) (a Y Y)) → Exists fun Z => a Z Z) False % 3.47/3.67 Clause #2 (by clausification #[1]): Eq (∀ (X : Iota), Exists fun Y => And (a X Y) (a Y Y)) True % 3.47/3.67 Clause #3 (by clausification #[1]): Eq (Exists fun Z => a Z Z) False % 3.47/3.67 Clause #4 (by clausification #[2]): ∀ (a_1 : Iota), Eq (Exists fun Y => And (a a_1 Y) (a Y Y)) True % 3.47/3.67 Clause #5 (by clausification #[4]): ∀ (a_1 a_2 : Iota), Eq (And (a a_1 (skS.0 0 a_1 a_2)) (a (skS.0 0 a_1 a_2) (skS.0 0 a_1 a_2))) True % 3.47/3.67 Clause #6 (by clausification #[5]): ∀ (a_1 a_2 : Iota), Eq (a (skS.0 0 a_1 a_2) (skS.0 0 a_1 a_2)) True % 3.47/3.67 Clause #8 (by clausification #[3]): ∀ (a_1 : Iota), Eq (a a_1 a_1) False % 3.47/3.67 Clause #9 (by superposition #[8, 6]): Eq False True % 3.47/3.67 Clause #10 (by clausification #[9]): False % 3.47/3.67 SZS output end Proof for theBenchmark.p %------------------------------------------------------------------------------