%------------------------------------------------------------------------------ % File : Duper---1.0 % Problem : SYN950+1 : TPTP v9.2.0. Released v3.1.0. % Transfm : none % Format : tptp:raw % Command : duper %s % Computer : n016.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 300s % DateTime : Fri Oct 3 08:08:18 PM UTC 2025 % Result : Theorem 3.66s 3.81s % Output : Proof 3.66s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.08/0.14 % Problem : SYN950+1 : TPTP v9.2.0. Released v3.1.0. % 0.08/0.15 % Command : duper %s % 0.15/0.36 % Computer : n016.cluster.edu % 0.15/0.36 % Model : x86_64 x86_64 % 0.15/0.36 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.15/0.36 % Memory : 8042.1875MB % 0.15/0.36 % OS : Linux 3.10.0-693.el7.x86_64 % 0.15/0.36 % CPULimit : 300 % 0.15/0.36 % WCLimit : 300 % 0.15/0.36 % DateTime : Thu Oct 2 15:04:38 EDT 2025 % 0.15/0.37 % CPUTime : % 3.66/3.81 SZS status Theorem for theBenchmark.p % 3.66/3.81 SZS output start Proof for theBenchmark.p % 3.66/3.81 Clause #0 (by assumption #[]): Eq (Not (∀ (A B : Iota), (∀ (Y : Iota), q Y → p Y) → Exists fun X => And (p X → p A) (q X → p B))) True % 3.66/3.81 Clause #1 (by clausification #[0]): Eq (∀ (A B : Iota), (∀ (Y : Iota), q Y → p Y) → Exists fun X => And (p X → p A) (q X → p B)) False % 3.66/3.81 Clause #2 (by clausification #[1]): ∀ (a : Iota), % 3.66/3.81 Eq (Not (∀ (B : Iota), (∀ (Y : Iota), q Y → p Y) → Exists fun X => And (p X → p (skS.0 0 a)) (q X → p B))) True % 3.66/3.81 Clause #3 (by clausification #[2]): ∀ (a : Iota), Eq (∀ (B : Iota), (∀ (Y : Iota), q Y → p Y) → Exists fun X => And (p X → p (skS.0 0 a)) (q X → p B)) False % 3.66/3.81 Clause #4 (by clausification #[3]): ∀ (a a_1 : Iota), % 3.66/3.81 Eq (Not ((∀ (Y : Iota), q Y → p Y) → Exists fun X => And (p X → p (skS.0 0 a)) (q X → p (skS.0 1 a a_1)))) True % 3.66/3.81 Clause #5 (by clausification #[4]): ∀ (a a_1 : Iota), % 3.66/3.81 Eq ((∀ (Y : Iota), q Y → p Y) → Exists fun X => And (p X → p (skS.0 0 a)) (q X → p (skS.0 1 a a_1))) False % 3.66/3.81 Clause #6 (by clausification #[5]): Eq (∀ (Y : Iota), q Y → p Y) True % 3.66/3.81 Clause #7 (by clausification #[5]): ∀ (a a_1 : Iota), Eq (Exists fun X => And (p X → p (skS.0 0 a)) (q X → p (skS.0 1 a a_1))) False % 3.66/3.81 Clause #8 (by clausification #[6]): ∀ (a : Iota), Eq (q a → p a) True % 3.66/3.81 Clause #9 (by clausification #[8]): ∀ (a : Iota), Or (Eq (q a) False) (Eq (p a) True) % 3.66/3.81 Clause #10 (by clausification #[7]): ∀ (a a_1 a_2 : Iota), Eq (And (p a → p (skS.0 0 a_1)) (q a → p (skS.0 1 a_1 a_2))) False % 3.66/3.81 Clause #11 (by clausification #[10]): ∀ (a a_1 a_2 : Iota), Or (Eq (p a → p (skS.0 0 a_1)) False) (Eq (q a → p (skS.0 1 a_1 a_2)) False) % 3.66/3.81 Clause #12 (by clausification #[11]): ∀ (a a_1 a_2 : Iota), Or (Eq (q a → p (skS.0 1 a_1 a_2)) False) (Eq (p a) True) % 3.66/3.81 Clause #13 (by clausification #[11]): ∀ (a a_1 a_2 : Iota), Or (Eq (q a → p (skS.0 1 a_1 a_2)) False) (Eq (p (skS.0 0 a_1)) False) % 3.66/3.81 Clause #14 (by clausification #[12]): ∀ (a : Iota), Or (Eq (p a) True) (Eq (q a) True) % 3.66/3.81 Clause #16 (by superposition #[14, 9]): ∀ (a : Iota), Or (Eq (p a) True) (Or (Eq True False) (Eq (p a) True)) % 3.66/3.81 Clause #17 (by clausification #[16]): ∀ (a : Iota), Or (Eq (p a) True) (Eq (p a) True) % 3.66/3.81 Clause #18 (by eliminate duplicate literals #[17]): ∀ (a : Iota), Eq (p a) True % 3.66/3.81 Clause #22 (by clausification #[13]): ∀ (a a_1 : Iota), Or (Eq (p (skS.0 0 a)) False) (Eq (p (skS.0 1 a a_1)) False) % 3.66/3.81 Clause #25 (by forward demodulation #[22, 18]): ∀ (a a_1 : Iota), Or (Eq True False) (Eq (p (skS.0 1 a a_1)) False) % 3.66/3.81 Clause #26 (by clausification #[25]): ∀ (a a_1 : Iota), Eq (p (skS.0 1 a a_1)) False % 3.66/3.81 Clause #27 (by superposition #[26, 18]): Eq False True % 3.66/3.81 Clause #28 (by clausification #[27]): False % 3.66/3.81 SZS output end Proof for theBenchmark.p %------------------------------------------------------------------------------