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Twee---2.7.THM-Prf.s

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%------------------------------------------------------------------------------
% File     : Twee---2.7
% Problem  : SYN953+1 : TPTP v9.3.1. Released v3.1.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : run_twee /export/starexec/sandbox/benchmark/theBenchmark.p

% Computer : n018.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8046.5625MB
% OS       : Linux 6.8.0-71-generic
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Tue Sep 29 01:48:40 PM UTC 2026

% Result   : Theorem 0.10s 0.24s
% Output   : Proof 0.10s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.02  % Problem  : SYN953+1 : TPTP v9.3.1. Released v3.1.0.
% 0.00/0.03  % Command  : run_twee /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.10/0.17  % Computer : n018.cluster.edu
% 0.10/0.17  % Model    : x86_64 x86_64
% 0.10/0.17  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.10/0.17  % Memory   : 8046.5625MB
% 0.10/0.17  % OS       : Linux 6.8.0-71-generic
% 0.10/0.17  % CPULimit : 300
% 0.10/0.17  % WCLimit  : 300
% 0.10/0.17  % DateTime : Mon Sep 28 17:18:39 UTC 2026
% 0.10/0.17  % CPUTime  : 
% 0.10/0.17  Running run_twee /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.10/0.24  Command-line arguments: --lhs-weight 1 --flip-ordering --normalise-queue-percent 10 --cp-renormalise-threshold 10 --complete-subsets --ground-joining-incomplete-limit 15 --flatten-every 2
% 0.10/0.24  
% 0.10/0.24  % SZS status Theorem
% 0.10/0.24  
% 0.10/0.24  % SZS output start Proof
% 0.10/0.24  Axiom 1 (prove_this): p(X) = true.
% 0.10/0.24  Axiom 2 (ifeq_axiom): ifeq(X, X, Y, Z) = Y.
% 0.10/0.24  Axiom 3 (prove_this_1): ifeq(p(X), true, q(X), true) = true.
% 0.10/0.24  
% 0.10/0.24  Goal 1 (prove_this_2): q(x) = true.
% 0.10/0.24  Proof:
% 0.10/0.24    q(x)
% 0.10/0.24  = { by axiom 2 (ifeq_axiom) R->L }
% 0.10/0.24    ifeq(true, true, q(x), true)
% 0.10/0.24  = { by axiom 1 (prove_this) R->L }
% 0.10/0.24    ifeq(p(x), true, q(x), true)
% 0.10/0.24  = { by axiom 3 (prove_this_1) }
% 0.10/0.24    true
% 0.10/0.24  % SZS output end Proof
% 0.10/0.24  
% 0.10/0.24  RESULT: Theorem (the conjecture is true).
%------------------------------------------------------------------------------