%------------------------------------------------------------------------------ % File : Duper---1.0 % Problem : SYN962+1 : TPTP v9.2.0. Released v3.1.0. % Transfm : none % Format : tptp:raw % Command : duper %s % Computer : n005.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 300s % DateTime : Fri Oct 3 08:08:19 PM UTC 2025 % Result : Theorem 3.55s 3.70s % Output : Proof 3.55s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.07/0.12 % Problem : SYN962+1 : TPTP v9.2.0. Released v3.1.0. % 0.07/0.13 % Command : duper %s % 0.14/0.34 % Computer : n005.cluster.edu % 0.14/0.34 % Model : x86_64 x86_64 % 0.14/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.14/0.34 % Memory : 8042.1875MB % 0.14/0.34 % OS : Linux 3.10.0-693.el7.x86_64 % 0.14/0.34 % CPULimit : 300 % 0.14/0.34 % WCLimit : 300 % 0.14/0.34 % DateTime : Thu Oct 2 15:27:23 EDT 2025 % 0.14/0.35 % CPUTime : % 3.55/3.70 SZS status Theorem for theBenchmark.p % 3.55/3.70 SZS output start Proof for theBenchmark.p % 3.55/3.70 Clause #0 (by assumption #[]): Eq (Not ((∀ (X : Iota), p X) → And (∀ (X : Iota), p X) (∀ (Y : Iota), p Y))) True % 3.55/3.70 Clause #1 (by clausification #[0]): Eq ((∀ (X : Iota), p X) → And (∀ (X : Iota), p X) (∀ (Y : Iota), p Y)) False % 3.55/3.70 Clause #2 (by clausification #[1]): Eq (∀ (X : Iota), p X) True % 3.55/3.70 Clause #3 (by clausification #[1]): Eq (And (∀ (X : Iota), p X) (∀ (Y : Iota), p Y)) False % 3.55/3.70 Clause #4 (by clausification #[2]): ∀ (a : Iota), Eq (p a) True % 3.55/3.70 Clause #5 (by clausification #[3]): Or (Eq (∀ (X : Iota), p X) False) (Eq (∀ (Y : Iota), p Y) False) % 3.55/3.70 Clause #6 (by clausification #[5]): ∀ (a : Iota), Or (Eq (∀ (Y : Iota), p Y) False) (Eq (Not (p (skS.0 0 a))) True) % 3.55/3.70 Clause #7 (by clausification #[6]): ∀ (a a_1 : Iota), Or (Eq (Not (p (skS.0 0 a))) True) (Eq (Not (p (skS.0 1 a_1))) True) % 3.55/3.70 Clause #8 (by clausification #[7]): ∀ (a a_1 : Iota), Or (Eq (Not (p (skS.0 1 a))) True) (Eq (p (skS.0 0 a_1)) False) % 3.55/3.70 Clause #9 (by clausification #[8]): ∀ (a a_1 : Iota), Or (Eq (p (skS.0 0 a)) False) (Eq (p (skS.0 1 a_1)) False) % 3.55/3.70 Clause #10 (by superposition #[9, 4]): ∀ (a : Iota), Or (Eq (p (skS.0 1 a)) False) (Eq False True) % 3.55/3.70 Clause #11 (by clausification #[10]): ∀ (a : Iota), Eq (p (skS.0 1 a)) False % 3.55/3.70 Clause #12 (by superposition #[11, 4]): Eq False True % 3.55/3.70 Clause #13 (by clausification #[12]): False % 3.55/3.70 SZS output end Proof for theBenchmark.p %------------------------------------------------------------------------------