%------------------------------------------------------------------------------ % File : Duper---1.0 % Problem : SYN968+1 : TPTP v9.2.0. Released v3.1.0. % Transfm : none % Format : tptp:raw % Command : duper %s % Computer : n003.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 300s % DateTime : Fri Oct 3 08:08:20 PM UTC 2025 % Result : Theorem 3.71s 3.91s % Output : Proof 3.71s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.07/0.12 % Problem : SYN968+1 : TPTP v9.2.0. Released v3.1.0. % 0.07/0.13 % Command : duper %s % 0.12/0.34 % Computer : n003.cluster.edu % 0.12/0.34 % Model : x86_64 x86_64 % 0.12/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.12/0.34 % Memory : 8042.1875MB % 0.12/0.34 % OS : Linux 3.10.0-693.el7.x86_64 % 0.12/0.34 % CPULimit : 300 % 0.12/0.34 % WCLimit : 300 % 0.12/0.34 % DateTime : Thu Oct 2 15:46:23 EDT 2025 % 0.12/0.34 % CPUTime : % 3.71/3.91 SZS status Theorem for theBenchmark.p % 3.71/3.91 SZS output start Proof for theBenchmark.p % 3.71/3.91 Clause #0 (by assumption #[]): Eq (Not (Exists fun X => ∀ (Y : Iota), p X → p Y)) True % 3.71/3.91 Clause #1 (by clausification #[0]): Eq (Exists fun X => ∀ (Y : Iota), p X → p Y) False % 3.71/3.91 Clause #2 (by clausification #[1]): ∀ (a : Iota), Eq (∀ (Y : Iota), p a → p Y) False % 3.71/3.91 Clause #3 (by clausification #[2]): ∀ (a a_1 : Iota), Eq (Not (p a → p (skS.0 0 a a_1))) True % 3.71/3.91 Clause #4 (by clausification #[3]): ∀ (a a_1 : Iota), Eq (p a → p (skS.0 0 a a_1)) False % 3.71/3.91 Clause #5 (by clausification #[4]): ∀ (a : Iota), Eq (p a) True % 3.71/3.91 Clause #6 (by clausification #[4]): ∀ (a a_1 : Iota), Eq (p (skS.0 0 a a_1)) False % 3.71/3.91 Clause #7 (by superposition #[6, 5]): Eq False True % 3.71/3.91 Clause #8 (by clausification #[7]): False % 3.71/3.91 SZS output end Proof for theBenchmark.p %------------------------------------------------------------------------------