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Duper---1.0.THM-Prf.s

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%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : SYN971+1 : TPTP v9.2.0. Released v3.1.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n021.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Oct  3 08:08:20 PM UTC 2025

% Result   : Theorem 3.48s 3.68s
% Output   : Proof 3.48s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.04/0.13  % Problem    : SYN971+1 : TPTP v9.2.0. Released v3.1.0.
% 0.12/0.14  % Command    : duper %s
% 0.13/0.35  % Computer : n021.cluster.edu
% 0.13/0.35  % Model    : x86_64 x86_64
% 0.13/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.35  % Memory   : 8042.1875MB
% 0.13/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.35  % CPULimit   : 300
% 0.13/0.35  % WCLimit    : 300
% 0.13/0.35  % DateTime   : Thu Oct  2 15:18:38 EDT 2025
% 0.13/0.35  % CPUTime    : 
% 3.48/3.68  SZS status Theorem for theBenchmark.p
% 3.48/3.68  SZS output start Proof for theBenchmark.p
% 3.48/3.68  Clause #0 (by assumption #[]): Eq (Not (Exists fun Y => (Exists fun X => p X) → p Y)) True
% 3.48/3.68  Clause #1 (by betaEtaReduce #[0]): Eq (Not (Exists fun Y => Exists p → p Y)) True
% 3.48/3.68  Clause #2 (by clausification #[1]): Eq (Exists fun Y => Exists p → p Y) False
% 3.48/3.68  Clause #3 (by clausification #[2]): ∀ (a : Iota), Eq (Exists p → p a) False
% 3.48/3.68  Clause #4 (by clausification #[3]): Eq (Exists p) True
% 3.48/3.68  Clause #5 (by clausification #[3]): ∀ (a : Iota), Eq (p a) False
% 3.48/3.68  Clause #6 (by clausification #[4]): ∀ (a : Iota), Eq (p (skS.0 0 a)) True
% 3.48/3.68  Clause #7 (by superposition #[5, 6]): Eq True False
% 3.48/3.68  Clause #8 (by clausification #[7]): False
% 3.48/3.68  SZS output end Proof for theBenchmark.p
%------------------------------------------------------------------------------