%------------------------------------------------------------------------------ % File : Duper---1.0 % Problem : SYN975+1 : TPTP v9.2.0. Released v3.1.0. % Transfm : none % Format : tptp:raw % Command : duper %s % Computer : n008.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 300s % DateTime : Fri Oct 3 08:08:20 PM UTC 2025 % Result : Theorem 4.92s 5.11s % Output : Proof 4.92s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.00/0.12 % Problem : SYN975+1 : TPTP v9.2.0. Released v3.1.0. % 0.12/0.13 % Command : duper %s % 0.12/0.34 % Computer : n008.cluster.edu % 0.12/0.34 % Model : x86_64 x86_64 % 0.12/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.12/0.34 % Memory : 8042.1875MB % 0.12/0.34 % OS : Linux 3.10.0-693.el7.x86_64 % 0.12/0.34 % CPULimit : 300 % 0.12/0.34 % WCLimit : 300 % 0.12/0.34 % DateTime : Thu Oct 2 15:38:23 EDT 2025 % 0.12/0.34 % CPUTime : % 4.92/5.11 SZS status Theorem for theBenchmark.p % 4.92/5.11 SZS output start Proof for theBenchmark.p % 4.92/5.11 Clause #0 (by assumption #[]): Eq (Not ((∀ (X Y : Iota), p X Y) → ∀ (X : Iota), p X X)) True % 4.92/5.11 Clause #1 (by clausification #[0]): Eq ((∀ (X Y : Iota), p X Y) → ∀ (X : Iota), p X X) False % 4.92/5.11 Clause #2 (by clausification #[1]): Eq (∀ (X Y : Iota), p X Y) True % 4.92/5.11 Clause #3 (by clausification #[1]): Eq (∀ (X : Iota), p X X) False % 4.92/5.11 Clause #4 (by clausification #[2]): ∀ (a : Iota), Eq (∀ (Y : Iota), p a Y) True % 4.92/5.11 Clause #5 (by clausification #[4]): ∀ (a a_1 : Iota), Eq (p a a_1) True % 4.92/5.11 Clause #6 (by clausification #[3]): ∀ (a : Iota), Eq (Not (p (skS.0 0 a) (skS.0 0 a))) True % 4.92/5.11 Clause #7 (by clausification #[6]): ∀ (a : Iota), Eq (p (skS.0 0 a) (skS.0 0 a)) False % 4.92/5.11 Clause #8 (by superposition #[7, 5]): Eq False True % 4.92/5.11 Clause #9 (by clausification #[8]): False % 4.92/5.11 SZS output end Proof for theBenchmark.p %------------------------------------------------------------------------------