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Duper---1.0.THM-Prf.s

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%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : SYN981+1 : TPTP v9.2.0. Released v3.1.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n027.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Oct  3 08:08:21 PM UTC 2025

% Result   : Theorem 3.46s 3.61s
% Output   : Proof 3.46s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12  % Problem    : SYN981+1 : TPTP v9.2.0. Released v3.1.0.
% 0.03/0.13  % Command    : duper %s
% 0.13/0.34  % Computer : n027.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit   : 300
% 0.13/0.34  % WCLimit    : 300
% 0.13/0.34  % DateTime   : Thu Oct  2 15:24:08 EDT 2025
% 0.13/0.35  % CPUTime    : 
% 3.46/3.61  SZS status Theorem for theBenchmark.p
% 3.46/3.61  SZS output start Proof for theBenchmark.p
% 3.46/3.61  Clause #0 (by assumption #[]): Eq (Not (And (∀ (X : Iota), p X → q X) (Exists fun Y => q Y → r Y) → Exists fun Z => p Z → r Z)) True
% 3.46/3.61  Clause #1 (by clausification #[0]): Eq (And (∀ (X : Iota), p X → q X) (Exists fun Y => q Y → r Y) → Exists fun Z => p Z → r Z) False
% 3.46/3.61  Clause #2 (by clausification #[1]): Eq (And (∀ (X : Iota), p X → q X) (Exists fun Y => q Y → r Y)) True
% 3.46/3.61  Clause #3 (by clausification #[1]): Eq (Exists fun Z => p Z → r Z) False
% 3.46/3.61  Clause #4 (by clausification #[2]): Eq (Exists fun Y => q Y → r Y) True
% 3.46/3.61  Clause #5 (by clausification #[2]): Eq (∀ (X : Iota), p X → q X) True
% 3.46/3.61  Clause #6 (by clausification #[4]): ∀ (a : Iota), Eq (q (skS.0 0 a) → r (skS.0 0 a)) True
% 3.46/3.61  Clause #7 (by clausification #[6]): ∀ (a : Iota), Or (Eq (q (skS.0 0 a)) False) (Eq (r (skS.0 0 a)) True)
% 3.46/3.61  Clause #8 (by clausification #[5]): ∀ (a : Iota), Eq (p a → q a) True
% 3.46/3.61  Clause #9 (by clausification #[8]): ∀ (a : Iota), Or (Eq (p a) False) (Eq (q a) True)
% 3.46/3.61  Clause #10 (by clausification #[3]): ∀ (a : Iota), Eq (p a → r a) False
% 3.46/3.61  Clause #11 (by clausification #[10]): ∀ (a : Iota), Eq (p a) True
% 3.46/3.61  Clause #12 (by clausification #[10]): ∀ (a : Iota), Eq (r a) False
% 3.46/3.61  Clause #13 (by superposition #[11, 9]): ∀ (a : Iota), Or (Eq True False) (Eq (q a) True)
% 3.46/3.61  Clause #14 (by clausification #[13]): ∀ (a : Iota), Eq (q a) True
% 3.46/3.61  Clause #15 (by backward demodulation #[14, 7]): ∀ (a : Iota), Or (Eq True False) (Eq (r (skS.0 0 a)) True)
% 3.46/3.61  Clause #17 (by clausification #[15]): ∀ (a : Iota), Eq (r (skS.0 0 a)) True
% 3.46/3.61  Clause #18 (by superposition #[17, 12]): Eq True False
% 3.46/3.61  Clause #19 (by clausification #[18]): False
% 3.46/3.61  SZS output end Proof for theBenchmark.p
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