%------------------------------------------------------------------------------ % File : cocATP---0.2.0 % Problem : SYN998^1 : TPTP v7.5.0. Released v3.7.0. % Transfm : none % Format : tptp:raw % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p % Computer : n001.cluster.edu---x86_64 x86_64--- ------Linux 3.10.0-693.el7.x86_64 % Model : Unavailable % CPU : Unavailable % Memory : Unavailable % OS : Unavailable % CPULimit : 300s % WCLimit : 0s % DateTime : Mon Mar 28 13:41:29 EDT 2022 % Result : Theorem 0.52s 0.75s % Output : Proof 0.52s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.07/0.12 % Problem : SYN998^1 : TPTP v7.5.0. Released v3.7.0. % 0.07/0.12 % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p % 0.13/0.33 % Computer : n001.cluster.edu % 0.13/0.33 % Model : x86_64 x86_64 % 0.13/0.33 % CPUModel : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.13/0.33 % RAMPerCPU : 8042.1875MB % 0.13/0.33 % OS : Linux 3.10.0-693.el7.x86_64 % 0.13/0.33 % CPULimit : 300 % 0.13/0.33 % DateTime : Thu Mar 10 22:43:09 EST 2022 % 0.13/0.33 % CPUTime : % 0.13/0.34 ModuleCmd_Load.c(213):ERROR:105: Unable to locate a modulefile for 'python/python27' % 0.13/0.34 Python 2.7.5 % 0.52/0.75 Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/'] % 0.52/0.75 FOF formula (<kernel.Constant object at 0x1a15b00>, <kernel.DependentProduct object at 0x1a15f38>) of role type named leibeq_decl % 0.52/0.75 Using role type % 0.52/0.75 Declaring leibeq:(fofType->(fofType->Prop)) % 0.52/0.75 FOF formula (((eq (fofType->(fofType->Prop))) leibeq) (fun (X:fofType) (Y:fofType)=> (forall (P:(fofType->Prop)), ((P X)->(P Y))))) of role definition named leibeq % 0.52/0.75 A new definition: (((eq (fofType->(fofType->Prop))) leibeq) (fun (X:fofType) (Y:fofType)=> (forall (P:(fofType->Prop)), ((P X)->(P Y))))) % 0.52/0.75 Defined: leibeq:=(fun (X:fofType) (Y:fofType)=> (forall (P:(fofType->Prop)), ((P X)->(P Y)))) % 0.52/0.75 FOF formula (forall (X:fofType), ((leibeq X) X)) of role conjecture named conj % 0.52/0.75 Conjecture to prove = (forall (X:fofType), ((leibeq X) X)):Prop % 0.52/0.75 Parameter fofType_DUMMY:fofType. % 0.52/0.75 We need to prove ['(forall (X:fofType), ((leibeq X) X))'] % 0.52/0.75 Parameter fofType:Type. % 0.52/0.75 Definition leibeq:=(fun (X:fofType) (Y:fofType)=> (forall (P:(fofType->Prop)), ((P X)->(P Y)))):(fofType->(fofType->Prop)). % 0.52/0.75 Trying to prove (forall (X:fofType), ((leibeq X) X)) % 0.52/0.75 Found x:(P X) % 0.52/0.75 Found (fun (x:(P X))=> x) as proof of (P X) % 0.52/0.75 Found (fun (P:(fofType->Prop)) (x:(P X))=> x) as proof of ((P X)->(P X)) % 0.52/0.75 Found (fun (X:fofType) (P:(fofType->Prop)) (x:(P X))=> x) as proof of ((leibeq X) X) % 0.52/0.75 Found (fun (X:fofType) (P:(fofType->Prop)) (x:(P X))=> x) as proof of (forall (X:fofType), ((leibeq X) X)) % 0.52/0.75 Got proof (fun (X:fofType) (P:(fofType->Prop)) (x:(P X))=> x) % 0.52/0.75 Time elapsed = 0.018399s % 0.52/0.75 node=5 cost=11.000000 depth=3 % 0.52/0.75 :::::::::::::::::::::: % 0.52/0.75 % SZS status Theorem for /export/starexec/sandbox/benchmark/theBenchmark.p % 0.52/0.75 % SZS output start Proof for /export/starexec/sandbox/benchmark/theBenchmark.p % 0.52/0.75 (fun (X:fofType) (P:(fofType->Prop)) (x:(P X))=> x) % 0.52/0.75 % SZS output end Proof for /export/starexec/sandbox/benchmark/theBenchmark.p %------------------------------------------------------------------------------