%------------------------------------------------------------------------------ % File : cocATP---0.2.0 % Problem : SYO004^1 : TPTP v7.5.0. Released v3.7.0. % Transfm : none % Format : tptp:raw % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p % Computer : n022.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 0s % DateTime : Tue Mar 29 00:50:22 EDT 2022 % Result : Theorem 0.54s 0.72s % Output : Proof 0.54s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.06/0.12 % Problem : SYO004^1 : TPTP v7.5.0. Released v3.7.0. % 0.06/0.12 % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p % 0.12/0.33 % Computer : n022.cluster.edu % 0.12/0.33 % Model : x86_64 x86_64 % 0.12/0.33 % CPUModel : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.12/0.33 % RAMPerCPU : 8042.1875MB % 0.12/0.33 % OS : Linux 3.10.0-693.el7.x86_64 % 0.12/0.33 % CPULimit : 300 % 0.12/0.33 % DateTime : Thu Mar 10 23:20:43 EST 2022 % 0.12/0.33 % CPUTime : % 0.12/0.34 ModuleCmd_Load.c(213):ERROR:105: Unable to locate a modulefile for 'python/python27' % 0.12/0.35 Python 2.7.5 % 0.54/0.72 Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/'] % 0.54/0.72 FOF formula (<kernel.Constant object at 0x1c99e60>, <kernel.DependentProduct object at 0x1c99ea8>) of role type named leibeq_decl % 0.54/0.72 Using role type % 0.54/0.72 Declaring leibeq:(fofType->(fofType->Prop)) % 0.54/0.72 FOF formula (((eq (fofType->(fofType->Prop))) leibeq) (fun (X:fofType) (Y:fofType)=> (forall (P:(fofType->Prop)), ((P X)->(P Y))))) of role definition named leibeq % 0.54/0.72 A new definition: (((eq (fofType->(fofType->Prop))) leibeq) (fun (X:fofType) (Y:fofType)=> (forall (P:(fofType->Prop)), ((P X)->(P Y))))) % 0.54/0.72 Defined: leibeq:=(fun (X:fofType) (Y:fofType)=> (forall (P:(fofType->Prop)), ((P X)->(P Y)))) % 0.54/0.72 FOF formula (forall (X:fofType) (Y:fofType), (((leibeq X) Y)->(((eq fofType) X) Y))) of role conjecture named conj % 0.54/0.72 Conjecture to prove = (forall (X:fofType) (Y:fofType), (((leibeq X) Y)->(((eq fofType) X) Y))):Prop % 0.54/0.72 Parameter fofType_DUMMY:fofType. % 0.54/0.72 We need to prove ['(forall (X:fofType) (Y:fofType), (((leibeq X) Y)->(((eq fofType) X) Y)))'] % 0.54/0.72 Parameter fofType:Type. % 0.54/0.72 Definition leibeq:=(fun (X:fofType) (Y:fofType)=> (forall (P:(fofType->Prop)), ((P X)->(P Y)))):(fofType->(fofType->Prop)). % 0.54/0.72 Trying to prove (forall (X:fofType) (Y:fofType), (((leibeq X) Y)->(((eq fofType) X) Y))) % 0.54/0.72 Found eq_substitution00000:=(eq_substitution0000 (fun (x2:fofType)=> x2)):((((eq fofType) X) Y)->(((eq fofType) X) Y)) % 0.54/0.72 Found (eq_substitution0000 (fun (x2:fofType)=> x2)) as proof of (((leibeq X) Y)->(((eq fofType) X) Y)) % 0.54/0.72 Found ((eq_substitution000 Y) (fun (x2:fofType)=> x2)) as proof of (((leibeq X) Y)->(((eq fofType) X) Y)) % 0.54/0.72 Found (((eq_substitution00 X) Y) (fun (x2:fofType)=> x2)) as proof of (((leibeq X) Y)->(((eq fofType) X) Y)) % 0.54/0.72 Found ((((eq_substitution0 fofType) X) Y) (fun (x2:fofType)=> x2)) as proof of (((leibeq X) Y)->(((eq fofType) X) Y)) % 0.54/0.72 Found (((((eq_substitution fofType) fofType) X) Y) (fun (x2:fofType)=> x2)) as proof of (((leibeq X) Y)->(((eq fofType) X) Y)) % 0.54/0.72 Found (fun (Y:fofType)=> (((((eq_substitution fofType) fofType) X) Y) (fun (x2:fofType)=> x2))) as proof of (((leibeq X) Y)->(((eq fofType) X) Y)) % 0.54/0.72 Found (fun (X:fofType) (Y:fofType)=> (((((eq_substitution fofType) fofType) X) Y) (fun (x2:fofType)=> x2))) as proof of (forall (Y:fofType), (((leibeq X) Y)->(((eq fofType) X) Y))) % 0.54/0.72 Found (fun (X:fofType) (Y:fofType)=> (((((eq_substitution fofType) fofType) X) Y) (fun (x2:fofType)=> x2))) as proof of (forall (X:fofType) (Y:fofType), (((leibeq X) Y)->(((eq fofType) X) Y))) % 0.54/0.72 Got proof (fun (X:fofType) (Y:fofType)=> (((((eq_substitution fofType) fofType) X) Y) (fun (x2:fofType)=> x2))) % 0.54/0.72 Time elapsed = 0.111593s % 0.54/0.72 node=12 cost=-458.000000 depth=7 % 0.54/0.72 :::::::::::::::::::::: % 0.54/0.72 % SZS status Theorem for /export/starexec/sandbox/benchmark/theBenchmark.p % 0.54/0.72 % SZS output start Proof for /export/starexec/sandbox/benchmark/theBenchmark.p % 0.54/0.72 (fun (X:fofType) (Y:fofType)=> (((((eq_substitution fofType) fofType) X) Y) (fun (x2:fofType)=> x2))) % 0.54/0.72 % SZS output end Proof for /export/starexec/sandbox/benchmark/theBenchmark.p %------------------------------------------------------------------------------