%------------------------------------------------------------------------------ % File : Duper---1.0 % Problem : SYO013^1 : TPTP v9.2.0. Released v3.7.0. % Transfm : none % Format : tptp:raw % Command : duper %s % Computer : n007.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 300s % DateTime : Fri Oct 3 08:08:25 PM UTC 2025 % Result : Theorem 3.45s 3.65s % Output : Proof 3.45s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.03/0.12 % Problem : SYO013^1 : TPTP v9.2.0. Released v3.7.0. % 0.03/0.13 % Command : duper %s % 0.13/0.34 % Computer : n007.cluster.edu % 0.13/0.34 % Model : x86_64 x86_64 % 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.13/0.34 % Memory : 8042.1875MB % 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64 % 0.13/0.34 % CPULimit : 300 % 0.13/0.34 % WCLimit : 300 % 0.13/0.34 % DateTime : Fri Oct 3 12:52:23 EDT 2025 % 0.13/0.34 % CPUTime : % 3.45/3.65 SZS status Theorem for theBenchmark.p % 3.45/3.65 SZS output start Proof for theBenchmark.p % 3.45/3.65 Clause #0 (by assumption #[]): Eq (Not (And (And a b) (p a) → p b)) True % 3.45/3.65 Clause #1 (by clausification #[0]): Eq (And (And a b) (p a) → p b) False % 3.45/3.65 Clause #2 (by clausification #[1]): Eq (And (And a b) (p a)) True % 3.45/3.65 Clause #3 (by clausification #[1]): Eq (p b) False % 3.45/3.65 Clause #4 (by clausification #[2]): Eq (p a) True % 3.45/3.65 Clause #5 (by clausification #[2]): Eq (And a b) True % 3.45/3.65 Clause #6 (by identity loobHoist #[4]): Or (Eq (p True) True) (Eq a False) % 3.45/3.65 Clause #8 (by identity loobHoist #[3]): Or (Eq (p True) False) (Eq b False) % 3.45/3.65 Clause #10 (by clausification #[5]): Eq b True % 3.45/3.65 Clause #11 (by clausification #[5]): Eq a True % 3.45/3.65 Clause #12 (by backward demodulation #[10, 8]): Or (Eq (p True) False) (Eq True False) % 3.45/3.65 Clause #13 (by backward demodulation #[11, 6]): Or (Eq (p True) True) (Eq True False) % 3.45/3.65 Clause #16 (by clausification #[12]): Eq (p True) False % 3.45/3.65 Clause #17 (by clausification #[13]): Eq (p True) True % 3.45/3.65 Clause #18 (by superposition #[17, 16]): Eq True False % 3.45/3.65 Clause #19 (by clausification #[18]): False % 3.45/3.65 SZS output end Proof for theBenchmark.p %------------------------------------------------------------------------------