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Duper---1.0.THM-Prf.s

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%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : SYO076^5 : TPTP v9.2.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n015.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Oct  3 08:08:33 PM UTC 2025

% Result   : Theorem 3.73s 3.92s
% Output   : Proof 3.73s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.08/0.14  % Problem    : SYO076^5 : TPTP v9.2.0. Released v4.0.0.
% 0.08/0.15  % Command    : duper %s
% 0.16/0.37  % Computer : n015.cluster.edu
% 0.16/0.37  % Model    : x86_64 x86_64
% 0.16/0.37  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.16/0.37  % Memory   : 8042.1875MB
% 0.16/0.37  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.16/0.37  % CPULimit   : 300
% 0.16/0.37  % WCLimit    : 300
% 0.16/0.37  % DateTime   : Fri Oct  3 13:43:38 EDT 2025
% 0.16/0.37  % CPUTime    : 
% 3.73/3.92  SZS status Theorem for theBenchmark.p
% 3.73/3.92  SZS output start Proof for theBenchmark.p
% 3.73/3.92  Clause #0 (by assumption #[]): Eq (Not (And cP (cP → cQ) → cQ)) True
% 3.73/3.92  Clause #1 (by clausification #[0]): Eq (And cP (cP → cQ) → cQ) False
% 3.73/3.92  Clause #2 (by clausification #[1]): Eq (And cP (cP → cQ)) True
% 3.73/3.92  Clause #3 (by clausification #[1]): Eq cQ False
% 3.73/3.92  Clause #4 (by clausification #[2]): Eq (cP → cQ) True
% 3.73/3.92  Clause #5 (by clausification #[2]): Eq cP True
% 3.73/3.92  Clause #6 (by clausification #[4]): Or (Eq cP False) (Eq cQ True)
% 3.73/3.92  Clause #7 (by backward demodulation #[5, 6]): Or (Eq True False) (Eq cQ True)
% 3.73/3.92  Clause #8 (by clausification #[7]): Eq cQ True
% 3.73/3.92  Clause #9 (by superposition #[8, 3]): Eq True False
% 3.73/3.92  Clause #10 (by clausification #[9]): False
% 3.73/3.92  SZS output end Proof for theBenchmark.p
%------------------------------------------------------------------------------