%------------------------------------------------------------------------------ % File : Duper---1.0 % Problem : SYO080^5 : TPTP v9.2.0. Released v4.0.0. % Transfm : none % Format : tptp:raw % Command : duper %s % Computer : n001.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 300s % DateTime : Fri Oct 3 08:08:33 PM UTC 2025 % Result : Theorem 3.53s 3.70s % Output : Proof 3.53s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.05/0.14 % Problem : SYO080^5 : TPTP v9.2.0. Released v4.0.0. % 0.05/0.15 % Command : duper %s % 0.15/0.37 % Computer : n001.cluster.edu % 0.15/0.37 % Model : x86_64 x86_64 % 0.15/0.37 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.15/0.37 % Memory : 8042.1875MB % 0.15/0.37 % OS : Linux 3.10.0-693.el7.x86_64 % 0.15/0.37 % CPULimit : 300 % 0.15/0.37 % WCLimit : 300 % 0.15/0.37 % DateTime : Fri Oct 3 14:27:38 EDT 2025 % 0.15/0.38 % CPUTime : % 3.53/3.70 SZS status Theorem for theBenchmark.p % 3.53/3.70 SZS output start Proof for theBenchmark.p % 3.53/3.70 Clause #0 (by assumption #[]): Eq (Not (((((cA → cB) → cA) → cA) → cB) → cB)) True % 3.53/3.70 Clause #1 (by clausification #[0]): Eq (((((cA → cB) → cA) → cA) → cB) → cB) False % 3.53/3.70 Clause #2 (by clausification #[1]): Eq ((((cA → cB) → cA) → cA) → cB) True % 3.53/3.70 Clause #3 (by clausification #[1]): Eq cB False % 3.53/3.70 Clause #4 (by clausification #[2]): Or (Eq (((cA → cB) → cA) → cA) False) (Eq cB True) % 3.53/3.70 Clause #5 (by clausification #[4]): Or (Eq cB True) (Eq ((cA → cB) → cA) True) % 3.53/3.70 Clause #6 (by clausification #[4]): Or (Eq cB True) (Eq cA False) % 3.53/3.70 Clause #7 (by clausification #[5]): Or (Eq cB True) (Or (Eq (cA → cB) False) (Eq cA True)) % 3.53/3.70 Clause #8 (by clausification #[7]): Or (Eq cB True) (Or (Eq cA True) (Eq cA True)) % 3.53/3.70 Clause #10 (by eliminate duplicate literals #[8]): Or (Eq cB True) (Eq cA True) % 3.53/3.70 Clause #11 (by superposition #[3, 10]): Or (Eq cA True) (Eq True False) % 3.53/3.70 Clause #12 (by clausification #[11]): Eq cA True % 3.53/3.70 Clause #14 (by backward demodulation #[12, 6]): Or (Eq cB True) (Eq True False) % 3.53/3.70 Clause #15 (by clausification #[14]): Eq cB True % 3.53/3.70 Clause #16 (by superposition #[15, 3]): Eq True False % 3.53/3.70 Clause #17 (by clausification #[16]): False % 3.53/3.70 SZS output end Proof for theBenchmark.p %------------------------------------------------------------------------------