%------------------------------------------------------------------------------ % File : Duper---1.0 % Problem : SYO092^5 : TPTP v9.2.0. Released v4.0.0. % Transfm : none % Format : tptp:raw % Command : duper %s % Computer : n006.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 300s % DateTime : Fri Oct 3 08:08:35 PM UTC 2025 % Result : Theorem 3.68s 3.85s % Output : Proof 3.68s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.03/0.12 % Problem : SYO092^5 : TPTP v9.2.0. Released v4.0.0. % 0.03/0.13 % Command : duper %s % 0.13/0.34 % Computer : n006.cluster.edu % 0.13/0.34 % Model : x86_64 x86_64 % 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.13/0.34 % Memory : 8042.1875MB % 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64 % 0.13/0.34 % CPULimit : 300 % 0.13/0.34 % WCLimit : 300 % 0.13/0.34 % DateTime : Fri Oct 3 12:54:23 EDT 2025 % 0.13/0.34 % CPUTime : % 3.68/3.85 SZS status Theorem for theBenchmark.p % 3.68/3.85 SZS output start Proof for theBenchmark.p % 3.68/3.85 Clause #0 (by assumption #[]): Eq (Not ((∀ (Xx : Iota), Exists fun Xy => And (cP Xx) (Or (cQ Xy) (cQ Xx))) → Exists fun Xz => And (cP Xz) (cQ Xz))) % 3.68/3.85 True % 3.68/3.85 Clause #1 (by clausification #[0]): Eq ((∀ (Xx : Iota), Exists fun Xy => And (cP Xx) (Or (cQ Xy) (cQ Xx))) → Exists fun Xz => And (cP Xz) (cQ Xz)) False % 3.68/3.85 Clause #2 (by clausification #[1]): Eq (∀ (Xx : Iota), Exists fun Xy => And (cP Xx) (Or (cQ Xy) (cQ Xx))) True % 3.68/3.85 Clause #3 (by clausification #[1]): Eq (Exists fun Xz => And (cP Xz) (cQ Xz)) False % 3.68/3.85 Clause #4 (by clausification #[2]): ∀ (a : Iota), Eq (Exists fun Xy => And (cP a) (Or (cQ Xy) (cQ a))) True % 3.68/3.85 Clause #5 (by clausification #[4]): ∀ (a a_1 : Iota), Eq (And (cP a) (Or (cQ (skS.0 0 a a_1)) (cQ a))) True % 3.68/3.85 Clause #6 (by clausification #[5]): ∀ (a a_1 : Iota), Eq (Or (cQ (skS.0 0 a a_1)) (cQ a)) True % 3.68/3.85 Clause #7 (by clausification #[5]): ∀ (a : Iota), Eq (cP a) True % 3.68/3.85 Clause #8 (by clausification #[6]): ∀ (a a_1 : Iota), Or (Eq (cQ (skS.0 0 a a_1)) True) (Eq (cQ a) True) % 3.68/3.86 Clause #9 (by clausification #[3]): ∀ (a : Iota), Eq (And (cP a) (cQ a)) False % 3.68/3.86 Clause #10 (by clausification #[9]): ∀ (a : Iota), Or (Eq (cP a) False) (Eq (cQ a) False) % 3.68/3.86 Clause #11 (by superposition #[10, 7]): ∀ (a : Iota), Or (Eq (cQ a) False) (Eq False True) % 3.68/3.86 Clause #12 (by clausification #[11]): ∀ (a : Iota), Eq (cQ a) False % 3.68/3.86 Clause #13 (by backward demodulation #[12, 8]): ∀ (a a_1 : Iota), Or (Eq (cQ (skS.0 0 a a_1)) True) (Eq False True) % 3.68/3.86 Clause #15 (by clausification #[13]): ∀ (a a_1 : Iota), Eq (cQ (skS.0 0 a a_1)) True % 3.68/3.86 Clause #16 (by superposition #[15, 12]): Eq True False % 3.68/3.86 Clause #17 (by clausification #[16]): False % 3.68/3.86 SZS output end Proof for theBenchmark.p %------------------------------------------------------------------------------