%------------------------------------------------------------------------------ % File : Duper---1.0 % Problem : SYO123^5 : TPTP v9.2.0. Released v4.0.0. % Transfm : none % Format : tptp:raw % Command : duper %s % Computer : n012.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 300s % DateTime : Fri Oct 3 08:08:37 PM UTC 2025 % Result : Theorem 4.88s 5.08s % Output : Proof 4.88s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.05/0.10 % Problem : SYO123^5 : TPTP v9.2.0. Released v4.0.0. % 0.05/0.11 % Command : duper %s % 0.10/0.31 % Computer : n012.cluster.edu % 0.10/0.31 % Model : x86_64 x86_64 % 0.10/0.31 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.10/0.31 % Memory : 8042.1875MB % 0.10/0.31 % OS : Linux 3.10.0-693.el7.x86_64 % 0.10/0.31 % CPULimit : 300 % 0.10/0.31 % WCLimit : 300 % 0.10/0.31 % DateTime : Fri Oct 3 13:45:08 EDT 2025 % 0.10/0.32 % CPUTime : % 4.88/5.08 SZS status Theorem for theBenchmark.p % 4.88/5.08 SZS output start Proof for theBenchmark.p % 4.88/5.08 Clause #0 (by assumption #[]): Eq (Not ((∀ (Xx : Iota), cP Xx) → And (cP a) (cP b))) True % 4.88/5.08 Clause #1 (by clausification #[0]): Eq ((∀ (Xx : Iota), cP Xx) → And (cP a) (cP b)) False % 4.88/5.08 Clause #2 (by clausification #[1]): Eq (∀ (Xx : Iota), cP Xx) True % 4.88/5.08 Clause #3 (by clausification #[1]): Eq (And (cP a) (cP b)) False % 4.88/5.08 Clause #4 (by clausification #[2]): ∀ (a : Iota), Eq (cP a) True % 4.88/5.08 Clause #5 (by clausification #[3]): Or (Eq (cP a) False) (Eq (cP b) False) % 4.88/5.08 Clause #6 (by forward demodulation #[5, 4]): Or (Eq True False) (Eq (cP b) False) % 4.88/5.08 Clause #7 (by clausification #[6]): Eq (cP b) False % 4.88/5.08 Clause #8 (by superposition #[7, 4]): Eq False True % 4.88/5.08 Clause #9 (by clausification #[8]): False % 4.88/5.08 SZS output end Proof for theBenchmark.p %------------------------------------------------------------------------------