%------------------------------------------------------------------------------ % File : Duper---1.0 % Problem : SYO125^5 : TPTP v9.2.0. Released v4.0.0. % Transfm : none % Format : tptp:raw % Command : duper %s % Computer : n018.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 300s % DateTime : Fri Oct 3 08:08:37 PM UTC 2025 % Result : Theorem 5.37s 5.58s % Output : Proof 5.37s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.05/0.10 % Problem : SYO125^5 : TPTP v9.2.0. Released v4.0.0. % 0.05/0.11 % Command : duper %s % 0.11/0.32 % Computer : n018.cluster.edu % 0.11/0.32 % Model : x86_64 x86_64 % 0.11/0.32 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.11/0.32 % Memory : 8042.1875MB % 0.11/0.32 % OS : Linux 3.10.0-693.el7.x86_64 % 0.11/0.32 % CPULimit : 300 % 0.11/0.32 % WCLimit : 300 % 0.11/0.32 % DateTime : Fri Oct 3 13:19:38 EDT 2025 % 0.11/0.32 % CPUTime : % 5.37/5.58 SZS status Theorem for theBenchmark.p % 5.37/5.58 SZS output start Proof for theBenchmark.p % 5.37/5.58 Clause #0 (by assumption #[]): Eq (Not (And (Iff cP cQ) (Iff cQ cR) → Iff cP cR)) True % 5.37/5.58 Clause #1 (by clausification #[0]): Eq (And (Iff cP cQ) (Iff cQ cR) → Iff cP cR) False % 5.37/5.58 Clause #2 (by clausification #[1]): Eq (And (Iff cP cQ) (Iff cQ cR)) True % 5.37/5.58 Clause #3 (by clausification #[1]): Eq (Iff cP cR) False % 5.37/5.58 Clause #4 (by clausification #[2]): Eq (Iff cQ cR) True % 5.37/5.58 Clause #5 (by clausification #[2]): Eq (Iff cP cQ) True % 5.37/5.58 Clause #6 (by clausification #[4]): Or (Eq cQ True) (Eq cR False) % 5.37/5.58 Clause #7 (by clausification #[4]): Or (Eq cQ False) (Eq cR True) % 5.37/5.58 Clause #8 (by clausification #[5]): Or (Eq cP True) (Eq cQ False) % 5.37/5.58 Clause #9 (by clausification #[5]): Or (Eq cP False) (Eq cQ True) % 5.37/5.58 Clause #10 (by clausification #[3]): Or (Eq cP False) (Eq cR False) % 5.37/5.58 Clause #11 (by clausification #[3]): Or (Eq cP True) (Eq cR True) % 5.37/5.58 Clause #12 (by superposition #[11, 6]): Or (Eq cP True) (Or (Eq cQ True) (Eq True False)) % 5.37/5.58 Clause #13 (by clausification #[12]): Or (Eq cP True) (Eq cQ True) % 5.37/5.58 Clause #14 (by superposition #[13, 9]): Or (Eq cQ True) (Or (Eq True False) (Eq cQ True)) % 5.37/5.58 Clause #16 (by clausification #[14]): Or (Eq cQ True) (Eq cQ True) % 5.37/5.58 Clause #17 (by eliminate duplicate literals #[16]): Eq cQ True % 5.37/5.58 Clause #19 (by backward demodulation #[17, 7]): Or (Eq True False) (Eq cR True) % 5.37/5.58 Clause #20 (by backward demodulation #[17, 8]): Or (Eq cP True) (Eq True False) % 5.37/5.58 Clause #23 (by clausification #[20]): Eq cP True % 5.37/5.58 Clause #24 (by backward demodulation #[23, 10]): Or (Eq True False) (Eq cR False) % 5.37/5.58 Clause #26 (by clausification #[24]): Eq cR False % 5.37/5.58 Clause #27 (by clausification #[19]): Eq cR True % 5.37/5.58 Clause #28 (by superposition #[27, 26]): Eq True False % 5.37/5.58 Clause #29 (by clausification #[28]): False % 5.37/5.58 SZS output end Proof for theBenchmark.p %------------------------------------------------------------------------------