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Duper---1.0.THM-Prf.s

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%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : SYO129^5 : TPTP v9.2.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n005.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Oct  3 08:08:38 PM UTC 2025

% Result   : Theorem 5.22s 5.47s
% Output   : Proof 5.22s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.02/0.07  % Problem    : SYO129^5 : TPTP v9.2.0. Released v4.0.0.
% 0.02/0.08  % Command    : duper %s
% 0.07/0.28  % Computer : n005.cluster.edu
% 0.07/0.28  % Model    : x86_64 x86_64
% 0.07/0.28  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.07/0.28  % Memory   : 8042.1875MB
% 0.07/0.28  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.07/0.28  % CPULimit   : 300
% 0.07/0.28  % WCLimit    : 300
% 0.07/0.28  % DateTime   : Fri Oct  3 14:17:53 EDT 2025
% 0.07/0.28  % CPUTime    : 
% 5.22/5.47  SZS status Theorem for theBenchmark.p
% 5.22/5.47  SZS output start Proof for theBenchmark.p
% 5.22/5.47  Clause #0 (by assumption #[]): Eq (Not ((∀ (Xx : Iota), cP Xx) → And (And (cP a) (cP b)) (cP c))) True
% 5.22/5.47  Clause #1 (by clausification #[0]): Eq ((∀ (Xx : Iota), cP Xx) → And (And (cP a) (cP b)) (cP c)) False
% 5.22/5.47  Clause #2 (by clausification #[1]): Eq (∀ (Xx : Iota), cP Xx) True
% 5.22/5.47  Clause #3 (by clausification #[1]): Eq (And (And (cP a) (cP b)) (cP c)) False
% 5.22/5.47  Clause #4 (by clausification #[2]): ∀ (a : Iota), Eq (cP a) True
% 5.22/5.47  Clause #5 (by clausification #[3]): Or (Eq (And (cP a) (cP b)) False) (Eq (cP c) False)
% 5.22/5.47  Clause #6 (by clausification #[5]): Or (Eq (cP c) False) (Or (Eq (cP a) False) (Eq (cP b) False))
% 5.22/5.47  Clause #7 (by forward demodulation #[6, 4]): Or (Eq (cP c) False) (Or (Eq True False) (Eq (cP b) False))
% 5.22/5.47  Clause #8 (by clausification #[7]): Or (Eq (cP c) False) (Eq (cP b) False)
% 5.22/5.47  Clause #9 (by forward demodulation #[8, 4]): Or (Eq (cP c) False) (Eq True False)
% 5.22/5.47  Clause #10 (by clausification #[9]): Eq (cP c) False
% 5.22/5.47  Clause #11 (by superposition #[10, 4]): Eq False True
% 5.22/5.47  Clause #12 (by clausification #[11]): False
% 5.22/5.47  SZS output end Proof for theBenchmark.p
%------------------------------------------------------------------------------