%------------------------------------------------------------------------------ % File : cocATP---0.2.0 % Problem : SYO134^5 : TPTP v7.5.0. Released v4.0.0. % Transfm : none % Format : tptp:raw % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p % Computer : n020.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 0s % DateTime : Tue Mar 29 00:50:43 EDT 2022 % Result : Theorem 0.47s 0.65s % Output : Proof 0.47s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.08/0.12 % Problem : SYO134^5 : TPTP v7.5.0. Released v4.0.0. % 0.08/0.13 % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p % 0.13/0.34 % Computer : n020.cluster.edu % 0.13/0.34 % Model : x86_64 x86_64 % 0.13/0.34 % CPUModel : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.13/0.34 % RAMPerCPU : 8042.1875MB % 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64 % 0.13/0.34 % CPULimit : 300 % 0.13/0.34 % DateTime : Fri Mar 11 16:05:26 EST 2022 % 0.13/0.34 % CPUTime : % 0.13/0.35 ModuleCmd_Load.c(213):ERROR:105: Unable to locate a modulefile for 'python/python27' % 0.13/0.35 Python 2.7.5 % 0.47/0.65 Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/'] % 0.47/0.65 FOF formula (<kernel.Constant object at 0x1820ef0>, <kernel.Constant object at 0x1820560>) of role type named a % 0.47/0.65 Using role type % 0.47/0.65 Declaring a:fofType % 0.47/0.65 FOF formula (<kernel.Constant object at 0x181c098>, <kernel.DependentProduct object at 0x17fac20>) of role type named cQ % 0.47/0.65 Using role type % 0.47/0.65 Declaring cQ:(fofType->Prop) % 0.47/0.65 FOF formula (<kernel.Constant object at 0x1817fc8>, <kernel.DependentProduct object at 0x17faa28>) of role type named cP % 0.47/0.65 Using role type % 0.47/0.65 Declaring cP:(fofType->Prop) % 0.47/0.65 FOF formula (((cP a)->(forall (Xx:fofType), (cQ Xx)))->((forall (Xx:fofType), (cP Xx))->(cQ a))) of role conjecture named cADDHYP1 % 0.47/0.65 Conjecture to prove = (((cP a)->(forall (Xx:fofType), (cQ Xx)))->((forall (Xx:fofType), (cP Xx))->(cQ a))):Prop % 0.47/0.65 We need to prove ['(((cP a)->(forall (Xx:fofType), (cQ Xx)))->((forall (Xx:fofType), (cP Xx))->(cQ a)))'] % 0.47/0.65 Parameter fofType:Type. % 0.47/0.65 Parameter a:fofType. % 0.47/0.65 Parameter cQ:(fofType->Prop). % 0.47/0.65 Parameter cP:(fofType->Prop). % 0.47/0.65 Trying to prove (((cP a)->(forall (Xx:fofType), (cQ Xx)))->((forall (Xx:fofType), (cP Xx))->(cQ a))) % 0.47/0.65 Found x00:=(x0 a):(cP a) % 0.47/0.65 Found (x0 a) as proof of (cP a) % 0.47/0.65 Found (x0 a) as proof of (cP a) % 0.47/0.65 Found (x1 (x0 a)) as proof of (cQ a) % 0.47/0.65 Found ((fun (x1:(cP a))=> ((x x1) a)) (x0 a)) as proof of (cQ a) % 0.47/0.65 Found (fun (x0:(forall (Xx:fofType), (cP Xx)))=> ((fun (x1:(cP a))=> ((x x1) a)) (x0 a))) as proof of (cQ a) % 0.47/0.65 Found (fun (x:((cP a)->(forall (Xx:fofType), (cQ Xx)))) (x0:(forall (Xx:fofType), (cP Xx)))=> ((fun (x1:(cP a))=> ((x x1) a)) (x0 a))) as proof of ((forall (Xx:fofType), (cP Xx))->(cQ a)) % 0.47/0.65 Found (fun (x:((cP a)->(forall (Xx:fofType), (cQ Xx)))) (x0:(forall (Xx:fofType), (cP Xx)))=> ((fun (x1:(cP a))=> ((x x1) a)) (x0 a))) as proof of (((cP a)->(forall (Xx:fofType), (cQ Xx)))->((forall (Xx:fofType), (cP Xx))->(cQ a))) % 0.47/0.65 Got proof (fun (x:((cP a)->(forall (Xx:fofType), (cQ Xx)))) (x0:(forall (Xx:fofType), (cP Xx)))=> ((fun (x1:(cP a))=> ((x x1) a)) (x0 a))) % 0.47/0.65 Time elapsed = 0.027943s % 0.47/0.65 node=8 cost=21.000000 depth=6 % 0.47/0.65 :::::::::::::::::::::: % 0.47/0.65 % SZS status Theorem for /export/starexec/sandbox/benchmark/theBenchmark.p % 0.47/0.65 % SZS output start Proof for /export/starexec/sandbox/benchmark/theBenchmark.p % 0.47/0.65 (fun (x:((cP a)->(forall (Xx:fofType), (cQ Xx)))) (x0:(forall (Xx:fofType), (cP Xx)))=> ((fun (x1:(cP a))=> ((x x1) a)) (x0 a))) % 0.47/0.65 % SZS output end Proof for /export/starexec/sandbox/benchmark/theBenchmark.p %------------------------------------------------------------------------------