%------------------------------------------------------------------------------ % File : cocATP---0.2.0 % Problem : SYO141^5 : TPTP v7.5.0. Released v4.0.0. % Transfm : none % Format : tptp:raw % Command : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p % Computer : n004.cluster.edu % Model : x86_64 x86_64 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz % Memory : 8042.1875MB % OS : Linux 3.10.0-693.el7.x86_64 % CPULimit : 300s % WCLimit : 0s % DateTime : Tue Mar 29 00:50:44 EDT 2022 % Result : Theorem 0.46s 0.65s % Output : Proof 0.46s % Verified : % SZS Type : - % Comments : %------------------------------------------------------------------------------ %----WARNING: Could not form TPTP format derivation %------------------------------------------------------------------------------ %----ORIGINAL SYSTEM OUTPUT % 0.11/0.11 % Problem : SYO141^5 : TPTP v7.5.0. Released v4.0.0. % 0.11/0.12 % Command : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p % 0.12/0.33 % Computer : n004.cluster.edu % 0.12/0.33 % Model : x86_64 x86_64 % 0.12/0.33 % CPUModel : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz % 0.12/0.33 % RAMPerCPU : 8042.1875MB % 0.12/0.33 % OS : Linux 3.10.0-693.el7.x86_64 % 0.12/0.33 % CPULimit : 300 % 0.12/0.33 % DateTime : Fri Mar 11 16:21:25 EST 2022 % 0.12/0.33 % CPUTime : % 0.12/0.34 ModuleCmd_Load.c(213):ERROR:105: Unable to locate a modulefile for 'python/python27' % 0.12/0.34 Python 2.7.5 % 0.46/0.65 Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox2/benchmark/', '/export/starexec/sandbox2/benchmark/'] % 0.46/0.65 FOF formula (<kernel.Constant object at 0xe7c3f8>, <kernel.Constant object at 0xe7c7e8>) of role type named a % 0.46/0.65 Using role type % 0.46/0.65 Declaring a:fofType % 0.46/0.65 FOF formula (<kernel.Constant object at 0xe76e18>, <kernel.DependentProduct object at 0xe7cf80>) of role type named cQ % 0.46/0.65 Using role type % 0.46/0.65 Declaring cQ:(fofType->Prop) % 0.46/0.65 FOF formula (<kernel.Constant object at 0xe7c3f8>, <kernel.Single object at 0xe7c128>) of role type named x % 0.46/0.65 Using role type % 0.46/0.65 Declaring x:fofType % 0.46/0.65 FOF formula (<kernel.Constant object at 0xe7c368>, <kernel.DependentProduct object at 0xe7c6c8>) of role type named cR % 0.46/0.65 Using role type % 0.46/0.65 Declaring cR:(fofType->Prop) % 0.46/0.65 FOF formula (<kernel.Constant object at 0xe7c128>, <kernel.DependentProduct object at 0x2b7fa14e1fc8>) of role type named cP % 0.46/0.65 Using role type % 0.46/0.65 Declaring cP:(fofType->Prop) % 0.46/0.65 FOF formula (((cP a)->(forall (Xx0:fofType), (cQ Xx0)))->((forall (Xx0:fofType), (cP Xx0))->((cR x)->(cQ a)))) of role conjecture named cADDHYP2 % 0.46/0.65 Conjecture to prove = (((cP a)->(forall (Xx0:fofType), (cQ Xx0)))->((forall (Xx0:fofType), (cP Xx0))->((cR x)->(cQ a)))):Prop % 0.46/0.65 We need to prove ['(((cP a)->(forall (Xx0:fofType), (cQ Xx0)))->((forall (Xx0:fofType), (cP Xx0))->((cR x)->(cQ a))))'] % 0.46/0.65 Parameter fofType:Type. % 0.46/0.65 Parameter a:fofType. % 0.46/0.65 Parameter cQ:(fofType->Prop). % 0.46/0.65 Parameter x:fofType. % 0.46/0.65 Parameter cR:(fofType->Prop). % 0.46/0.65 Parameter cP:(fofType->Prop). % 0.46/0.65 Trying to prove (((cP a)->(forall (Xx0:fofType), (cQ Xx0)))->((forall (Xx0:fofType), (cP Xx0))->((cR x)->(cQ a)))) % 0.46/0.65 Found x000:=(x00 a):(cP a) % 0.46/0.65 Found (x00 a) as proof of (cP a) % 0.46/0.65 Found (x00 a) as proof of (cP a) % 0.46/0.65 Found (x01 (x00 a)) as proof of (cQ a) % 0.46/0.65 Found ((fun (x2:(cP a))=> ((x0 x2) a)) (x00 a)) as proof of (cQ a) % 0.46/0.65 Found (fun (x1:(cR x))=> ((fun (x2:(cP a))=> ((x0 x2) a)) (x00 a))) as proof of (cQ a) % 0.46/0.65 Found (fun (x00:(forall (Xx0:fofType), (cP Xx0))) (x1:(cR x))=> ((fun (x2:(cP a))=> ((x0 x2) a)) (x00 a))) as proof of ((cR x)->(cQ a)) % 0.46/0.65 Found (fun (x0:((cP a)->(forall (Xx0:fofType), (cQ Xx0)))) (x00:(forall (Xx0:fofType), (cP Xx0))) (x1:(cR x))=> ((fun (x2:(cP a))=> ((x0 x2) a)) (x00 a))) as proof of ((forall (Xx0:fofType), (cP Xx0))->((cR x)->(cQ a))) % 0.46/0.65 Found (fun (x0:((cP a)->(forall (Xx0:fofType), (cQ Xx0)))) (x00:(forall (Xx0:fofType), (cP Xx0))) (x1:(cR x))=> ((fun (x2:(cP a))=> ((x0 x2) a)) (x00 a))) as proof of (((cP a)->(forall (Xx0:fofType), (cQ Xx0)))->((forall (Xx0:fofType), (cP Xx0))->((cR x)->(cQ a)))) % 0.46/0.65 Got proof (fun (x0:((cP a)->(forall (Xx0:fofType), (cQ Xx0)))) (x00:(forall (Xx0:fofType), (cP Xx0))) (x1:(cR x))=> ((fun (x2:(cP a))=> ((x0 x2) a)) (x00 a))) % 0.46/0.65 Time elapsed = 0.035547s % 0.46/0.65 node=10 cost=30.000000 depth=7 % 0.46/0.65 :::::::::::::::::::::: % 0.46/0.65 % SZS status Theorem for /export/starexec/sandbox2/benchmark/theBenchmark.p % 0.46/0.65 % SZS output start Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p % 0.46/0.65 (fun (x0:((cP a)->(forall (Xx0:fofType), (cQ Xx0)))) (x00:(forall (Xx0:fofType), (cP Xx0))) (x1:(cR x))=> ((fun (x2:(cP a))=> ((x0 x2) a)) (x00 a))) % 0.46/0.65 % SZS output end Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p %------------------------------------------------------------------------------